LM2904NG ON Semiconductor, LM2904NG Datasheet - Page 9

IC OPAMP DUAL LOW POWER 8DIP

LM2904NG

Manufacturer Part Number
LM2904NG
Description
IC OPAMP DUAL LOW POWER 8DIP
Manufacturer
ON Semiconductor
Datasheet

Specifications of LM2904NG

Amplifier Type
General Purpose
Number Of Circuits
2
Slew Rate
0.6 V/µs
Gain Bandwidth Product
1MHz
Current - Input Bias
45nA
Voltage - Input Offset
2000µV
Current - Supply
1.5mA
Current - Output / Channel
40mA
Voltage - Supply, Single/dual (±)
3 V ~ 32 V, ±1.5 V ~ 16 V
Operating Temperature
-40°C ~ 105°C
Mounting Type
Through Hole
Package / Case
8-DIP (0.300", 7.62mm)
Number Of Channels
2
Common Mode Rejection Ratio (min)
50 dB
Input Voltage Range (max)
Positive Rail - 5.7 V
Input Voltage Range (min)
Negative Rail
Input Offset Voltage
7 mV
Input Bias Current (max)
250 nA
Output Current (typ)
40 mA
Operating Supply Voltage
32 V
Supply Current
1.2 mA
Maximum Operating Temperature
+ 105 C
Minimum Operating Temperature
- 40 C
Dual Supply Voltage
+/- 3 V, +/- 5 V, +/- 9 V
Maximum Dual Supply Voltage
+/- 16 V
Minimum Dual Supply Voltage
+/- 1.5 V
Mounting Style
Through Hole
Shutdown
No
Supply Voltage (max)
32 V
Supply Voltage (min)
3 V
Technology
Bipolar
Voltage Gain Db
100 dB
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
Output Type
-
-3db Bandwidth
-
Lead Free Status / Rohs Status
Lead free / RoHS Compliant
Other names
LM2904NGOS

Available stocks

Company
Part Number
Manufacturer
Quantity
Price
Part Number:
LM2904NG
Manufacturer:
ON Semiconductor
Quantity:
8 700
Part Number:
LM2904NG
Manufacturer:
ON/安森美
Quantity:
20 000
V
V
ref
ref
=
1
2
V
CC
1/2
LM358
+
-
f =
Triangle Wave
C
Figure 15. Function Generator
Output
4 CR
R1 + R
f
R1
C
R
f
V
R1
ref
if,
75 k
R3
R3 =
R2 + R1
100 k
R2 R1
1/2
LM358
+
-
300 k
R2
http://onsemi.com
Square
Wave
Output
9
V
in
Figure 16. Multiple Feedback Bandpass Filter
For less than 10% error from operational amplifier.
Where f
If source impedance varies, filter may be preceded with voltage
follower buffer to stabilize filter parameters.
R1
Then:
Given:
Choose value f
o
and BW are expressed in Hz.
R2
C
R3 =
R1 =
R2 =
A(f
C
4Q
p f
2 A(f
f
o
o
) = gain at center frequency
R3
Q
2
= center frequency
o
R1 R3
o
, C
R1 -R3
C
o
)
R3
V
ref
1/2
LM358
-
+
V
CC
CO = 10 C
V
Q
BW
ref
o
CO
f
=
o
1
2
< 0.1
V
CC
V
O

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