LM2902VDTBR2G ON Semiconductor, LM2902VDTBR2G Datasheet - Page 8

• Manufacturer Part Number: LM2902VDTBR2G
• Description: IC OPAMP QUAD SGL SUPPLY 14TSSOP
• Manufacturer: ON Semiconductor

Specifications of LM2902VDTBR2G

• Amplifier Type: General Purpose
• Number Of Circuits: 4
• Slew Rate: 0.6 V/µs
• Gain Bandwidth Product: 1MHz
• Current - Input Bias: 90nA
• Voltage - Input Offset: 2000µV
• Current - Supply: 1.4mA
• Current - Output / Channel: 40mA
• Voltage - Supply, Single/dual (±): 3 V ~ 32 V, ±1.5 V ~ 16 V
• Operating Temperature: -40°C ~ 125°C
• Mounting Type: Surface Mount
• Package / Case: 14-TSSOP
• Number Of Channels: 4
• Voltage Gain Db: 100 dB
• Common Mode Rejection Ratio (min): 50 dB
• Input Voltage Range (max): Positive Rail - 5.7 V
• Input Voltage Range (min): Negative Rail
• Input Offset Voltage: 7 mV
• Output Current (typ): 40 mA
• Operating Supply Voltage: 32 V
• Supply Current: 1.2 mA
• Maximum Operating Temperature: + 125 C
• Mounting Style: SMD/SMT
• Maximum Dual Supply Voltage: +/- 16 V
• Minimum Operating Temperature: - 40 C
• Lead Free Status / RoHS Status: Lead free / RoHS Compliant
• Output Type: -
• -3db Bandwidth: -
• Lead Free Status / Rohs Status: Details
• Other names: LM2902VDTBR2GOS

Figure 13. High Impedance Differential Amplifier
e
e
V
1
2
in
MC1403
V
R1
CC
C1
-
+
LM324
-
LM324
+
1/4
1/4
Figure 11. Voltage Reference
a R1
b R1
e
o
= C (1 + a + b) (e
R2
R2
2.5 V
V
ref
C R
C R
1
1
R2
-
+
LM324
V
1/4
O
R1
LM324
-
+
2
1/4
= 2.5 V
- e
V
R
C
CC
1
R
)
+
-
LM324
1 +
1/4
R
R1
R2
R1
V
R
O
Bandpass
Figure 15. Bi−Quad Filter
Output
http://onsemi.com
Vref
e
o
-
+
LM324
1/4
C
8
V
ref
R
V
V
V
ref
-
+
LM324
in
ref
1/4
=
R3
Where: T
Where:
V
1
2
ref
100 k
V
R1
CC
Figure 14. Comparator with Hysteresis
V
V
inH
inL
T
Figure 12. Wien Bridge Oscillator
H =
BP
N
=
V
=
10 k
ref
= Passband Notch Gain
= Center Frequency Gain
R1 + R2
R1 + R2
R1 + R2
+
-
LM324
R
-
+
R1
1/4
R1
LM324
100 k
R1
R2
1/4
C1
5.0 k
(V
(V
(V
OL
OH
OH
-
+
C
LM324
50 k
1/4
- V
- V
- V
For: f
For:
For:
For:
R
ref
V
ref
OL
V
Notch Output
O
) + V
CC
) + V
)
f
R1 = QR
R2 =
R3 = T
C1 = 10C
Q = 10
T
T
o
V
C
V
o
BP
N
V
OH
= 2 p RC
OL
ref
ref
= 1.0 kHz
O
= 1
= 1
T
R1
N R2
BP
1
For: f
f
o
=
V
R = 160 kW
C = 0.001 mF
R1 = 1.6 MW
R2 = 1.6 MW
R3 = 1.6 MW
O
2 p RC
V
R = 16 kW
C = 0.01 mF
V
o
Hysteresis
ref
inL
1
= 1.0 kHz
V
=
ref
1
2
V
inH
V
CC