EVAL-AD7450ACBZ Analog Devices Inc, EVAL-AD7450ACBZ Datasheet - Page 22

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EVAL-AD7450ACBZ

Manufacturer Part Number
EVAL-AD7450ACBZ
Description
EVALUATION BOARD I.C.
Manufacturer
Analog Devices Inc
Datasheet

Specifications of EVAL-AD7450ACBZ

Lead Free Status / RoHS Status
Lead free / RoHS Compliant
AD7440/AD7450A
Timing Example 1
Having F
cycle time of
A cycle consists of
Therefore, if t
This 296 ns satisfies the requirement of 290 ns for t
From Figure 40, t
where t
satisfying the minimum requirement of 60 ns.
1/Throughput = 1/1,000,000 = 1 μs
t
10 ns + 12.5(1/18 MHz) + t
t
2.5(1/F
2
ACQ
+ 12.5(1/F
8
= 35 ns. This allows a value of 122 ns for t
SCLK
= 296 ns
SCLK
= 18 MHz and a throughput rate of 1 MSPS gives a
2
= 10 ns
) + t
SCLK
ACQ
8
) + t
comprises
+ t
QUIET
ACQ
= 1 μs
ACQ
= 1 μs
QUIET
ACQ
.
,
Rev. C | Page 22 of 28
Timing Example 2
Having F
cycle time of
A cycle consists of
Therefore, if t
This 664 ns satisfies the requirement of 290 ns for t
From Figure 40, t
where t
satisfying the minimum requirement of 60 ns.
As in this example and with other slower clock values, the signal
may already be acquired before the conversion is complete, but
it is still necessary to leave 60 ns minimum t
conversions. In Timing Example 2, the signal should be fully
acquired at approximately Point C in Figure 40.
1/Throughput = 1/315,000 = 3.174 μs
t
10 ns + 12.5(1/5 MHz) + t
t
2.5(1/F
2
ACQ
+ 12.5(1/F
8
= 35 ns. This allows a value of 129 ns for t
SCLK
= 664 ns
SCLK
= 5 MHz and a throughput rate of 315 kSPS gives a
2
is 10 ns
) + t
SCLK
ACQ
8
) + t
+ t
comprises
QUIET
ACQ
= 3.174 μs
ACQ
= 3.174 μs
QUIET
between
QUIET,
ACQ
.

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