AD7450ARMZ Analog Devices Inc, AD7450ARMZ Datasheet - Page 12

• Manufacturer Part Number: AD7450ARMZ
• Description: IC ADC 12BIT DIFF IN 1MSPS 8MSOP
• Manufacturer: Analog Devices Inc

Specifications of AD7450ARMZ

• Data Interface: DSP, MICROWIRE™, QSPI™, Serial, SPI™
• Number Of Bits: 12
• Sampling Rate (per Second): 1M
• Number Of Converters: 1
• Power Dissipation (max): 9.25mW
• Voltage Supply Source: Single Supply
• Operating Temperature: -40°C ~ 85°C
• Mounting Type: Surface Mount
• Package / Case: 8-TSSOP, 8-MSOP (0.118", 3.00mm Width)
• Resolution (bits): 12bit
• Input Channel Type: Differential
• Supply Voltage Range - Analogue: 2.7V To 3.3V, 4.75V To 5.25V
• Supply Current: 1.8mA
• No. Of Pins: 8
• Operating: RoHS Compliant
• Sampling Rate: 1MSPS
• Rohs Compliant: Yes
• Lead Free Status / RoHS Status: Lead free / RoHS Compliant
• For Use With: EVAL-AD7450CBZ - BOARD EVALUATION FOR AD7450
• Lead Free Status / RoHS Status: Lead free / RoHS Compliant

AD7450
Analog Input Structure
Figure 11 shows the equivalent circuit of the analog input struc-
ture of the AD7450. The four diodes provide ESD protection
for the analog inputs. Care must be taken to ensure that the
analog input signals never exceed the supply rails by more than
300 mV. This will cause these diodes to become forward biased
and start conducting into the substrate. These diodes can conduct
up to 10 mA without causing irreversible damage to the part.
The capacitors, C1, in Figure 11 are typically 4 pF and can prima-
rily be attributed to pin capacitance. The resistors are lumped
components made up of the ON resistance of the switches. The
value of these resistors is typically about 100 Ω. The capacitors,
C2, are the ADC’s sampling capacitors and have a capacitance
of 16 pF typically.
For ac applications, removing high-frequency components from
the analog input signal is recommended by the use of an RC
low-pass filter on the relevant analog input pins. In applications
where harmonic distortion and signal-to-noise ratio are critical,
the analog input should be driven from a low impedance source.
Large source impedances will significantly affect the ac perfor-
mance of the ADC. This may necessitate the use of an input
buffer amplifier. The choice of the op amp will be a function of
the particular application.
When no amplifier is used to drive the analog input, the source
impedance should be limited to values lower than 1 kΩ. The
maximum source impedance will depend on the amount of
Figure 10. Examples of the Analog Inputs to V
and V
Figure 11. Equivalent Analog Input Circuit
Conversion Phase—Switches Open
Track Phase—Switches Closed
IN–
V
V
IN–
IN+
COMMON-MODE (CM)
COMMON-MODE (CM)
for Different Values of V
CM
CM
CM
C1
C1
CM
MIN
MAX
MAX
MIN
= 0.625V
= 4.42V
= 1.25V
= 3.75V
V
V
DD
DD
D
D
D
D
REFERENCE = 1.25V
REFERENCE = 2.5V
V
V
V
V
IN
IN
IN
IN
–
–
REF
R1
R1
1.25V p-p
2.5V p-p
for V
C2
C2
DD
= 5 V
IN+
–12–
total harmonic distortion (THD) that can be tolerated. The THD
will increase as the source impedance increases and the perfor-
mance will degrade. Figure 12 shows a graph of the THD versus
the analog input signal frequency for different source impedances.
Figure 13 shows a graph of the THD versus the analog input
frequency for V
at 1 MSPS and 833 kSPS with a SCLK of 18 MHz and
15 MHz, respectively. In this case, the source impedance is 10 Ω.
DRIVING DIFFERENTIAL INPUTS
Differential operation requires that V
neously driven with two equal signals that are 180
The common mode must be set up externally and has a range
that is determined by V
amplifier used to drive the analog inputs (see Figures 8 and 9).
Differential modes of operation with either an ac or dc input
provide the best THD performance over a wide frequency range.
Since not all applications have a signal preconditioned for
differential operation, there is often a need to perform single-
ended-to-differential conversion.
Figure 12. THD vs. Analog Input Frequency for
Various Source Impedances for V
Figure 13. THD vs. Analog Input Frequency for 3 V
± 10% and 5 V ± 5% Supply Voltages
–70
–72
–74
–76
–78
–80
–82
–60
–65
–70
–75
–80
–85
–90
–95
10
10
T
T
A
A
= 25 C
= 25 C
V
DD
DD
= 3.3V
of 5 V ± 5% and 3 V ± 10%, while sampling
REF
INPUT FREQUENCY – kHz
INPUT FREQUENCY – kHz
, the power supply, and the particular
V
V
DD
DD
V
R
DD
= 2.7V
IN
= 5.25V
100
100
= 100
= 5V
IN+
V
R
DD
IN
and V
= 1k
= 3V
V
R
DD
V
DD
IN
DD
= 1k
= 5V
= 5 V and 3 V
V
R
= 4.75V
IN–
DD
IN
= 100
= 3V
o
be simulta-
out of phase.
1000
1000
REV. 0