LM4839LQ/NOPB National Semiconductor, LM4839LQ/NOPB Datasheet - Page 20

IC AMP AUDIO PWR 2.2W STER 28LLP

LM4839LQ/NOPB

Manufacturer Part Number
LM4839LQ/NOPB
Description
IC AMP AUDIO PWR 2.2W STER 28LLP
Manufacturer
National Semiconductor
Series
Boomer®r
Type
Class ABr
Datasheet

Specifications of LM4839LQ/NOPB

Output Type
2-Channel (Stereo) with Stereo Headphones
Max Output Power X Channels @ Load
2.2W x 2 @ 3 Ohm; 95mW x 2 @ 32 Ohm
Voltage - Supply
2.7 V ~ 5.5 V
Features
Bass Boost, Depop, Input Multiplexer, Mute, Shutdown, Thermal Protection, Volume Control
Mounting Type
Surface Mount
Package / Case
28-LLP
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
Other names
LM4839LQ
LM4839LQTR
www.national.com
AUDIO POWER AMPLIFIER
DESIGN
Audio Amplifier Design: Driving 1W into an 8
The following are the desired operational parameters:
Bandwidth:
The design begins by specifying the minimum supply voltage
necessary to obtain the specified output power. One way to
find the minimum supply voltage is to use the Output Power
vs Supply Voltage curve in the Typical Performance Char-
acteristics section. Another way, using Equation (11), is to
calculate the peak output voltage necessary to achieve the
desired output power for a given load impedance. To ac-
count for the amplifier’s dropout voltage, two additional volt-
ages, based on the Dropout Voltage vs Supply Voltage in the
Typical Performance Characteristics curves, must be
added to the result obtained by Equation (11). The result is
Equation (12).
The Output Power vs Supply Voltage graph for an 8
indicates a minimum supply voltage of 4.6V. This is easily
met by the commonly used 5V supply voltage. The additional
voltage creates the benefit of headroom, allowing the
LM4839 to produce peak output power in excess of 1W
without clipping or other audible distortion. The choice of
supply voltage must also not create a situation that violates
of maximum power dissipation as explained above in the
Power Dissipation section.
After satisfying the LM4839’s power dissipation require-
ments, the minimum differential gain needed to achieve 1W
dissipation in an 8
Thus, a minimum overall gain of 2.83 allows the LM4839’s to
reach full output swing and maintain low noise and THD+N
performance.
Power Output:
Load Impedance:
Input Level:
Input Impedance:
V
DD
(V
OUTPEAK
load is found using Equation (13).
+ (V
OD TOP
100 Hz−20 kHz
+ V
OD BOT
))
±
Load
1 W
0.25 dB
1 V
20 k
RMS
RMS
load
(10)
(12)
(11)
8
20
The last step in this design example is setting the amplifier’s
−3dB frequency bandwidth. To achieve the desired
pass band magnitude variation limit, the low frequency re-
sponse must extend to at least one-fifth the lower bandwidth
limit and the high frequency response must extend to at least
five times the upper bandwidth limit. The gain variation for
both response limits is 0.17dB, well within the
desired limit. The results are an
and an
As mentioned in the Selecting Proper External Compo-
nents section, R
a highpass filter that sets the amplifier’s lower bandpass
frequency limit. Find the coupling capacitor’s value using
Equation (17).
The result is
Use a 0.39µF capacitor, the closest standard value.
The product of the desired high frequency cutoff (100kHz in
this example) and the differential gain A
upper passband response limit. With A
100kHz, the closed-loop gain bandwidth product (GBWP) is
300kHz. This is less than the LM4839’s 3.5MHz GBWP. With
this margin, the amplifier can be used in designs that require
more differential gain while avoiding performance,restricting
bandwidth limitations.
RECOMMENDED PRINTED
CIRCUIT BOARD LAYOUT
Figures 4 through 8 show the recommended four-layer PC
board layout that is optimized for the 8-pin LQ-packaged
LM4839 and associated external components. This circuit is
designed for use with an external 5V supply and 4
ers.
This circuit board is easy to use. Apply 5V and ground to the
board’s V
speakers between the board’s −OUTA and +OUTA and
OUTB and +OUTB pads.
DD
and GND pads, respectively. Connect 4
i
(Right & Left) and C
1/(2
f
H
f
= 20kHz x 5 = 100kHz
L
*
C
20k
= 100Hz/5 = 20Hz
i
1/(2 R
*
20Hz) = 0.397µF
i
f
L
i
)
(Right & Left) create
VD
VD
, determines the
= 3 and f
±
±
0.25dB
0.25dB
speak-
(13)
(14)
(15)
(16)
H
=

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