LTC6101HV Linear Technology, LTC6101HV Datasheet - Page 8

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LTC6101HV

Manufacturer Part Number
LTC6101HV
Description
High-Side Current Sense Amplifier
Manufacturer
Linear Technology
Datasheets

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LTC6101/LTC6101HV
BLOCK DIAGRAM
APPLICATIONS INFORMATION
PIN FUNCTIONS
OUT: Current Output. OUT will source a current that is pro-
portional to the sense voltage into an external resistor.
V
Operation).
–IN: The internal sense amplifi er will drive IN
potential as IN
the output current I
developed across the external R
+IN: Must be tied to the system load end of the sense
resistor, either directly or through a resistor.
The LTC6101 high side current sense amplifi er (Figure 1)
provides accurate monitoring of current through a user-
selected sense resistor. The sense voltage is amplifi ed by
a user-selected gain and level shifted from the positive
power supply to a ground-referred output. The output
signal is analog and may be used as is or processed with
an output fi lter.
Theory of Operation
An internal sense amplifi er loop forces IN
same potential as IN
8
: Negative Supply (or Ground for Single-Supply
I
LOAD
+
. A resistor (R
L
O
A
D
OUT
+
= V
. Connecting an external resis-
R
V
SENSE
SENSE
SENSE
Figure 1. LTC6101/LTC6101HV Block Diagram and Typical Connection
IN
+
/R
) tied from V
SENSE
R
IN
IN
. V
+IN
–IN
LTC6101/LTC6101HV
SENSE
(Figure 1).
is the voltage
+
5k
5k
to have the
to the same
to IN
sets
10V
+
V
this pin. The circuit may be confi gured so that the
LTC6101 supply current is or is not monitored along
with the system load current. To monitor only system
load current, connect V
sense resistor. To monitor the total current, including the
LTC6101 current, connect V
of the sense resistor.
tor, R
R
R
fl ow through R
sense amplifi er will not conduct this input current,
so it will fl ow through an internal MOSFET to the output
pin.
The output current can be transformed into a voltage by
adding a resistor from OUT to V
then V
+
IN
SENSE
: Positive Supply Pin. Supply current is drawn through
V
V
+
that is the same as the sense voltage across
IN
O
, between IN
. A corresponding current, V
10V
= V
V
BATTERY
+ I
OUT
OUT
IN
6101 BD
. The high impedance inputs of the
• R
and V
OUT
I
+
OUT
to the more positive side of the
R
.
OUT
V
+
OUT
+
to the more negative side
forces a potential across
= V
SENSE
. The output voltage is
x
R
R
OUT
IN
SENSE
/R
IN
, will
6101fg

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