LMX2325TM National Semiconductor, LMX2325TM Datasheet - Page 15

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LMX2325TM

Manufacturer Part Number
LMX2325TM
Description
IC FREQ SYNTHESIZER 20-TSSOP
Manufacturer
National Semiconductor
Series
PLLatinum™r
Type
PLL Frequency Synthesizerr
Datasheet

Specifications of LMX2325TM

Pll
Yes
Input
CMOS, TTL
Output
CMOS
Number Of Circuits
1
Ratio - Input:output
1:1
Differential - Input:output
Yes/No
Frequency - Max
2.5GHz
Divider/multiplier
Yes/No
Voltage - Supply
2.7 V ~ 5.5 V
Operating Temperature
-40°C ~ 85°C
Mounting Type
Surface Mount
Package / Case
20-TSSOP
Frequency-max
2.5GHz
Lead Free Status / RoHS Status
Contains lead / RoHS non-compliant
Other names
*LMX2325TM

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Application Information
LOOP FILTER DESIGN
A block diagram of the basic phase locked loop is shown.
An example of a passive loop filter configuration, including
the transfer function of the loop filter, is shown in Figure 2 .
Define the time constants which determine the pole and zero
frequencies of the filter transfer function by letting
and
The PLL linear model control circuit is shown along with the
open loop transfer function in Figure 3 . Using the phase
detector and VCO gain constants [K and K
loop filter transfer function [Z(s)], the open loop Bode plot
can be calculated. The loop bandwidth is shown on the Bode
plot ( p) as the point of unity gain. The phase margin is
shown to be the difference between the phase at the unity
gain point and −180˚.
FIGURE 2. 2nd Order Passive Filter
T2 = R2 • C2
DS012339-30
FIGURE 1. Basic Charge Pump Phase Locked Loop
VCO
] and the
DS012339-32
(1)
(2)
15
Open Loop Gain =
Closed Loop Gain =
Thus we can calculate the 3rd order PLL Open Loop Gain in
terms of frequency
From equation 3 we can see that the phase term will be
dependent on the single pole and zero such that
By setting
we find the frequency point corresponding to the phase
inflection point in terms of the filter time constants T1 and T2.
This relationship is given in equation 6.
= K Z(s) K
FIGURE 3. Open Loop Transfer Function
( ) = tan
VCO
−1
/Ns
(
i
/
o
e
/
• T2) − tan
= H(s) G(s)
i
= G(s)/[1 + H(s) G(s)]
−1
(
• T1) + 180˚
DS012339-31
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DS012339-29
(3)
(4)
(5)
(6)

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