IRFS4310 IRF, IRFS4310 Datasheet - Page 5

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IRFS4310

Manufacturer Part Number
IRFS4310
Description
Power MOSFET
Manufacturer
IRF
Datasheet

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Fig 15. Maximum Avalanche Energy vs. Temperature
1000
800
600
400
200
0
25
0.0001
1000
0.001
0.01
100
Starting T J , Junction Temperature (°C)
10
0.1
1
1.0E-06
1
1E-006
50
Fig 13. Maximum Effective Transient Thermal Impedance, Junction-to-Case
Duty Cycle = Single Pulse
D = 0.50
TOP
BOTTOM 1% Duty Cycle
I D = 75A
75
0.20
0.10
0.05
0.02
0.01
100
SINGLE PULSE
( THERMAL RESPONSE )
0.05
0.01
0.10
Single Pulse
1.0E-05
1E-005
Fig 14. Typical Avalanche Current vs.Pulsewidth
125
150
175
t 1 , Rectangular Pulse Duration (sec)
1.0E-04
0.0001
Notes on Repetitive Avalanche Curves , Figures 14, 15:
(For further info, see AN-1005 at www.irf.com)
1. Avalanche failures assumption:
2. Safe operation in Avalanche is allowed as long asT
3. Equation below based on circuit and waveforms shown in Figures 16a, 16b.
4. P
5. BV = Rated breakdown voltage (1.3 factor accounts for voltage increase
6. I
7. ∆T
tav (sec)
Purely a thermal phenomenon and failure occurs at a temperature far in
excess of T
during avalanche).
25°C in Figure 14, 15).
t
D = Duty cycle in avalanche = t
Z
av
av =
thJC
D (ave)
= Allowable avalanche current.
=
τ
Average time in avalanche.
(D, t
Allowable rise in junction temperature, not to exceed T
J
τ
J
τ
1
= Average power dissipation per single avalanche pulse.
Ci= τi/Ri
τ
av
1
Ci
) = Transient thermal resistance, see Figures 13)
jmax
1.0E-03
i/Ri
R
0.001
1
R
. This is validated for every part type.
1
P
τ
2
D (ave)
R
τ
Allowed avalanche Current vs
avalanche
assuming ∆Tj = 25°C due to
avalanche losses. Note: In no
case should Tj be allowed to
exceed Tjmax
2
2
R
2
τ
= 1/2 ( 1.3·BV·I
I
E
C
av
Notes:
1. Duty Factor D = t1/t2
2. Peak Tj = P dm x Zthjc + Tc
τ
AS (AR)
= 2DT/ [1.3·BV·Z
av
Ri (°C/W)
·f
pulsewidth,
1.0E-02
= P
0.1962
0.2542
0.01
D (ave)
av
) = DT/ Z
·t
th
av
0.00117
0.016569
]
τi (sec)
tav
jmax
thJC
jmax
is not exceeded.
1.0E-01
(assumed as
0.1
5

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