LM2576T-ADJG ON Semiconductor, LM2576T-ADJG Datasheet - Page 12

IC REG SW 3A ADJ STEPDWN TO220-5

LM2576T-ADJG

Manufacturer Part Number
LM2576T-ADJG
Description
IC REG SW 3A ADJ STEPDWN TO220-5
Manufacturer
ON Semiconductor
Type
Step-Down (Buck)r
Datasheet

Specifications of LM2576T-ADJG

Internal Switch(s)
Yes
Synchronous Rectifier
No
Number Of Outputs
1
Voltage - Output
1.23 ~ 37 V
Current - Output
3A
Frequency - Switching
52kHz
Voltage - Input
7 ~ 40 V
Operating Temperature
-40°C ~ 125°C
Mounting Type
Through Hole
Package / Case
TO-220-5 (Straight Leads)
Output Voltage
1.23 V to 37 V
Output Current
3 A
Input Voltage
4.75 V to 40 V
Switching Frequency
52 KHz
Operating Temperature Range
- 40 C to + 125 C
Mounting Style
Through Hole
Duty Cycle (max)
98 %
Primary Input Voltage
40V
No. Of Outputs
1
No. Of Pins
5
Filter Terminals
Through Hole
Rohs Compliant
Yes
Dc
0739
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
Power - Output
-
Lead Free Status / Rohs Status
Lead free / RoHS Compliant
Other names
LM2576T-ADJGOS

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Procedure (Adjustable Output Version: LM2576−ADJ) (continued)
4. Inductor Selection (L1)
5. Output Capacitor Selection (C
A. Use the following formula to calculate the inductor Volt x
B. Match the calculated E x T value with the corresponding
C. Next step is to identify the inductance region intersected by
D. From the inductor code, identify the inductor value. Then
A. Since the LM2576 is a forward−mode switching regulator
B. Capacitor values between 10 mF and 2000 mF will satisfy
C. Due to the fact that the higher voltage electrolytic capacitors
microsecond [V x ms] constant:
number on the vertical axis of the Inductor Value Selection
Guide shown in Figure 22. This E x T constant is a
measure of the energy handling capability of an inductor and
is dependent upon the type of core, the core area, the
number of turns, and the duty cycle.
the E x T value and the maximum load current value on the
horizontal axis shown in Figure 25.
select an appropriate inductor from Table 2.
The inductor chosen must be rated for a switching
frequency of 52 kHz and for a current rating of 1.15 x I
The inductor current rating can also be determined by
calculating the inductor peak current:
where t
For additional information about the inductor, see the
inductor section in the “External Components” section of
this data sheet.
with voltage mode control, its open loop 2−pole−1−zero
frequency characteristic has the dominant pole−pair
determined by the output capacitor and inductor values.
For stable operation, the capacitor must satisfy the
following requirement:
the loop requirements for stable operation. To achieve an
acceptable output ripple voltage and transient response, the
output capacitor may need to be several times larger than
the above formula yields.
generally have lower ESR (Equivalent Series Resistance)
numbers, the output capacitor’s voltage rating should be at
least 1.5 times greater than the output voltage. For a 5.0 V
regulator, a rating of at least 8.0 V is appropriate, and a 10 V
or 16 V rating is recommended.
E x T + V
I
on
p(max)
C out w 13, 300
is the “on” time of the power switch and
in
+
– V out
I
t on +
Load(max)
Procedure
V out x L [μH]
V out
V out
V in
V
V in(max)
in
)
out
x 10
x 1.0
)
V in – V out t on
f osc
F[Hz]
6
2L
[μF]
[V x ms]
http://onsemi.com
Load
LM2576
.
12
4. Inductor Selection (L1)
5. Output Capacitor Selection (C
A. Calculate E x T [V x ms] constant:
B. E x T = 80 [V x ms]
C. I
D. Proper inductor value = 150 mH
A.
Inductance Region = H150
Choose the inductor from Table 2.
To achieve an acceptable ripple voltage, select
C
Load(max)
out
E x T + ( 25 – 8.0 ) x 8.0
= 680 mF electrolytic capacitor.
C out w 13, 300 x
= 2.5 A
Example
8 x 150
25
25
x 1000
out
52
)
+ 332.5 μF
+ 80 [V x ms]

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