L08052R2BEWTR AVX Corporation, L08052R2BEWTR Datasheet - Page 4
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L08052R2BEWTR
Manufacturer Part Number
L08052R2BEWTR
Description
INDUCTOR THIN FILM 2.2NH 0805
Manufacturer
AVX Corporation
Series
Accu-L®r
Type
Thin Filmr
Datasheet
1.L06031R5CGSTR.pdf
(5 pages)
Specifications of L08052R2BEWTR
Inductance
2.2nH
Current
1A
Tolerance
±0.1nH
Dc Resistance (dcr)
70 mOhm Max
Q @ Freq
82 @ 1.7GHz
Self Resonant Freq
10GHz
Package / Case
0805 (2012 Metric)
Mounting Type
Surface Mount
Operating Temperature
-55°C ~ 125°C
Frequency - Test
450MHz
Applications
General Purpose
Lead Free Status / RoHS Status
Contains lead / RoHS non-compliant
Shielding
-
Current - Saturation
-
Current - Temperature Rise
-
Accu-L
SMD High-Q RF Inductor
FINAL QUALITY INSPECTION
Finished parts are tested for electrical parameters and visual/
mechanical characteristics.
ENVIRONMENTAL CHARACTERISTICS
Solderability
Leach Resistance
Storage
Shear
Rapid Change of
Temperature
Bend Strength
Temperature
Coefficient of
Inductance
(TCL)
TEST
®
0603 and 0805
Components completely immersed in
a solder bath at 235 ± 5°C for 2 secs.
Components completely immersed in
a solder bath at 260 ±5°C for 60 secs.
12 months minimum with components
stored in “as received” packaging.
Components mounted to a substrate.
A force of 5N applied normal to the
line joining the terminations and in
a line parallel to the substrate.
Components mounted to a substrate.
5 cycles -55°C to +125°C.
Tested as shown in diagram
Component placed in
environmental chamber
-55°C to +125°C.
1mm
deflection
CONDITIONS
45mm
45mm
Parts are 100% tested for inductance at 450MHz. Parts are
100% tested for R
sample basis for:
• Q at test frequency
• Static Humidity Resistance: 85°C, 85% RH, 160 hours
• Endurance: 125°C, I
Terminations to be well tinned.
No visible damage.
Dissolution of termination faces
≤ 15% of area.
Dissolution of termination edges
≤ 25% of length.
Good solderability
No visible damage
No visible damage
No visible damage
+0 to +125 ppm/°C
(typical)
T
1
DC
= 25°C
. Each pro duc tion lot is eval u at ed on a
REQUIREMENT
R
, 4 hours
TCL =
L
1
L
(T
2
-L
2
-T
1
1
)
• 10
6
31
2