ACPL-227-560E Avago Technologies US Inc., ACPL-227-560E Datasheet - Page 5
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ACPL-227-560E
Manufacturer Part Number
ACPL-227-560E
Description
DC Phototx Coupler Dual,L/F+T/R+VD
Manufacturer
Avago Technologies US Inc.
Datasheet
1.ACPL-227-500E.pdf
(8 pages)
Specifications of ACPL-227-560E
Number Of Channels
2
Input Type
DC
Voltage - Isolation
3000Vrms
Current Transfer Ratio (min)
50% @ 5mA
Current Transfer Ratio (max)
600% @ 5mA
Voltage - Output
80V
Current - Output / Channel
50mA
Current - Dc Forward (if)
50mA
Vce Saturation (max)
400mV
Output Type
Transistor
Mounting Type
Surface Mount
Package / Case
SO-8
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
Electrical Specifications (DC)
Over recommended ambient temperature at 25qC unless otherwise specified.
Figure 1. Switching Time Test Circuit
5
Parameter
Forward Voltage
Reverse Current
Terminal Capacitance
Collector Dark Current
Collector-Emitter
Breakdown Voltage
Emitter-Collector
Breakdown Voltage
Current Transfer Ratio
(ACPL-227 Only)
Current Transfer Ratio
(ACPL-247 Only)
Saturated CTR
Collector-Emitter
Saturation Voltage
Isolation Resistance
Floating Capacitance
Cut-off Frequency
(-3dB)
Response Time (Rise)
Response Time (Fall)
Turn-on Time
Turn-off Time
Turn-ON Time
Storage Time
Turn-OFF Time
Common Mode
Rejection Voltage
Symbol
V
I
C
I
BV
BV
CTR
CTR
CTR(sat)
V
R
C
F
t
t
t
t
t
T
t
CMR
R
CEO
r
f
on
off
ON
OFF
C
S
F
CE(sat)
iso
t
F
CEO
ECO
Min.
-
-
-
-
80
7
50
100
-
-
5x10
-
-
-
-
-
-
-
-
-
-
10
Typ.
1.2
-
30
-
-
-
-
-
60
-
1x10
0.6
80
2
3
3
3
2
25
40
10
11
Max.
1.4
10
-
100
-
-
600
600
-
0.4
-
1
-
-
-
-
-
-
-
-
-
Units
V
PA
pF
nA
V
V
%
%
%
V
:
pF
kHz
Ps
Ps
Ps
Ps
Ps
Ps
Ps
kV/Ps
Figure 2. Frequency Response Test Circuit
Test Conditions
I
V
V = 0, f = 1MHz
V
I
I
I
I
I
I
DC500V, R.H. 40~60%
V = 0, f = 1MHz
V
R
V
R
V
R
Ta=25ºC, RL=470:,
V
I
V
F
C
E
F
F
F
F
F
R
CE
CC
L
CC
L
CC
L
CM
np
=1mA, V
=0mA, V
= 20mA
= 100 PA, I
= 5 mA, V
= 5 mA, V
= 8mA, I
= 0.5 mA, I
= 100:
= 100:
= 1.9k:
= 5V
=100mV
= 48V, I
= 5V, I
= 10V, I
= 5V, I
=1.5kV(peak),
CE
CC
C
F
C
F
C
CE
CE
= 16 mA,
= 2 mA,
= 2.4mA
=9V,
= 0.4V
= 0 mA
F
F
= 2 mA,
= 0 mA
= 5V
= 5V
= 0 mA
Note
Fig.6
Fig.12
CTR=(I
CTR=(I
Fig.14
Fig. 2,19
Fig. 1
Fig. 1, 17
Fig.20
C
C
/I
/I
F
F
)* 100%
)* 100%