60CPQ150PBF Vishay, 60CPQ150PBF Datasheet - Page 3

DIODE SCHOTTKY 150V 30A TO247AC

60CPQ150PBF

Manufacturer Part Number
60CPQ150PBF
Description
DIODE SCHOTTKY 150V 30A TO247AC
Manufacturer
Vishay
Datasheet

Specifications of 60CPQ150PBF

Voltage - Forward (vf) (max) @ If
830mV @ 30A
Current - Reverse Leakage @ Vr
100µA @ 150V
Current - Average Rectified (io) (per Diode)
30A
Voltage - Dc Reverse (vr) (max)
150V
Diode Type
Schottky
Speed
Fast Recovery =< 500ns, > 200mA (Io)
Diode Configuration
1 Pair Common Cathode
Mounting Type
Through Hole, Radial
Package / Case
TO-247-3 (Straight Leads), TO-247AC
Product
Schottky Diodes
Peak Reverse Voltage
150 V
Forward Continuous Current
30 A
Max Surge Current
2300 A
Configuration
Dual Common Cathode
Forward Voltage Drop
0.99 V @ 60 A
Maximum Reverse Leakage Current
100 uA
Operating Temperature Range
- 55 C to + 175 C
Mounting Style
Through Hole
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
Reverse Recovery Time (trr)
-
Lead Free Status / Rohs Status
Lead free / RoHS Compliant
Other names
*60CPQ150PBF
VS-60CPQ150PBF
VS-60CPQ150PBF
VS60CPQ150PBF
VS60CPQ150PBF

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Document Number: 93367
Revision: 21-Aug-08
Fig. 1 - Maximum Forward Voltage Drop Characteristics
0
0.01
0.1
0.00001
V
1
FM
0.5
- Forward Voltage Drop (V)
1.0
(Per Leg)
Fig. 4 - Maximum Thermal Impedance Z
Fig. 3 - Typical Junction Capacitance vs. Reverse Voltage (Per Leg)
0.0001
(thermal resistance)
1.5
For technical questions, contact: diodes-tech@vishay.com
T
T
T
Single pulse
J
J
J
= 175 °C
= 125 °C
= 25 °C
Schottky Rectifier, 2 x 30 A
2.0
0
0.001
t
20
1
2.5
- Rectangular Pulse Duration (s)
V
T
40
J
R
= 25 °C
- Reverse Voltage (V)
60
D = 0.75
D = 0.50
D = 0.33
D = 0.25
D = 0.20
0.01
80
thJC
100
Characteristics (Per Leg)
120
140
Notes:
1. Duty factor D = t
2. Peak T
0
Fig. 2 - Typical Values of Reverse Current vs.
0.1
Vishay High Power Products
20
160
T
T
J
J
T
J
= P
= 25 °C
Reverse Voltage (Per Leg)
V
J
40
= 50 °C
T
= 75 °C
R
P
J
DM
- Reverse Voltage (V)
DM
= 100 °C
T
J
x Z
60
1
= 125 °C
t
/t
1
thJC
T
2
1
t
J
2
= 150 °C
80
+ T
C
T
100
J
60CPQ150
= 175 °C
120
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10
140
160
3

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