LT6552CS8#TRPBF Linear Technology, LT6552CS8#TRPBF Datasheet - Page 7

IC OPAMP VID DIFF SGL 3.3V 8SOIC

LT6552CS8#TRPBF

Manufacturer Part Number
LT6552CS8#TRPBF
Description
IC OPAMP VID DIFF SGL 3.3V 8SOIC
Manufacturer
Linear Technology
Datasheet

Specifications of LT6552CS8#TRPBF

Applications
Differential
Number Of Circuits
1
-3db Bandwidth
75MHz
Slew Rate
600 V/µs
Current - Supply
14mA
Current - Output / Channel
70mA
Voltage - Supply, Single/dual (±)
3 V ~ 12.6 V, ±1.5 V ~ 6.3 V
Mounting Type
Surface Mount
Package / Case
8-SOIC (0.154", 3.90mm Width)
Lead Free Status / RoHS Status
Lead free / RoHS Compliant

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Quantity
Price
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LT
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Part Number:
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Quantity:
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Company:
Part Number:
LT6552CS8#TRPBF
Manufacturer:
LINEAR/凌特
Quantity:
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TYPICAL PERFOR A CE CHARACTERISTICS
100m
–10
–20
–30
–40
–50
–60
10m
20
18
16
14
12
10
8
6
4
2
0
0
1
0.01
0
Supply Current vs Supply Voltage
0
Shutdown Pin Current vs
Shutdown Pin Voltage
Output Saturation Voltage vs
Load Current (Output High)
V
V
V
S
CM
T
T
T
S
T
A
A
= 5V, 0V
A
A
= 5V, 0V
= –55 C
= 1V
= 125 C
= 125 C
T
= 25 C
2
A
SOURCING LOAD CURRENT (mA)
1
SHUTDOWN PIN VOLTAGE (V)
TOTAL SUPPLY VOLTAGE (V)
= 25 C
0.1
4
T
T
A
A
2
= –55 C
T
= 125 C
A
= 25 C
6
1
3
8
T
A
10
= –55 C
W
4
10
6552 G01
6552 G07
6552 G04
U
12
100
5
100m
–10
–12
–14
–16
–18
–20
–22
–24
10m
75
70
65
60
55
50
45
40
1m
–50
–50
1
0.01
Output Short-Circuit Current vs
Temperature
Input Bias Current vs Temperature
Output Saturation Voltage vs
Load Current (Output Low)
V
V
S
CM
V
T
S
= 5V, 0V
V
–25
–25
A
= 5V, 0V
S
= 1V
T
= 125 C
A
= 5V, 0V
SINKING LOAD CURRENT (mA)
= –55 C
V
S
0.1
= 3.3V, 0V
0
0
TEMPERATURE ( C)
TEMPERATURE ( C)
25
25
T
A
1
= 25 C
50
50
75
75
10
100
100
6552 G02
6552 G08
6552 G05
125
125
100
–10
–12
–14
–16
–18
–20
–22
–24
–4
–6
–8
16
14
12
10
80
75
70
65
60
8
6
4
2
0
2.5
–50
0
Input Bias Current vs Common
Mode Voltage
Supply Current vs
Shutdown Pin Voltage
Output Short-Circuit Current vs
Temperature
V
V
V
V
S
S
CM
S
T
= 5V, 0V
= 5V, 0V
= 5V
–25
A
= 1V
= 125 C
3.0
COMMON MODE VOLTAGE (V)
SHUTDOWN PIN VOLTAGE (V)
1
T
T
A
0
TEMPERATURE ( C)
A
= 25 C
T
= –55 C
A
3.5
2
= –55 C
25
T
A
SINKING CURRENT
= 25 C
T
SOURCING CURRENT
A
50
= 125 C
4.0
LT6552
3
75
4.5
4
100
6552 G03
6552 G06
6552 G09
7
6552f
5.0
125
5

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