LT1256CS#TRPBF Linear Technology, LT1256CS#TRPBF Datasheet - Page 7
LT1256CS#TRPBF
Manufacturer Part Number
LT1256CS#TRPBF
Description
IC AMP VIDEO FADE CONTRLD 14SOIC
Manufacturer
Linear Technology
Datasheet
1.LT1256CSPBF.pdf
(24 pages)
Specifications of LT1256CS#TRPBF
Applications
Current Feedback
Number Of Circuits
1
-3db Bandwidth
40MHz
Slew Rate
300 V/µs
Current - Supply
14.5mA
Current - Output / Channel
40mA
Voltage - Supply, Single/dual (±)
5 V ~ 30 V, ±2.5 V ~ 15 V
Mounting Type
Surface Mount
Package / Case
14-SOIC (0.154", 3.90mm Width)
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
Available stocks
Company
Part Number
Manufacturer
Quantity
Price
TYPICAL PERFORMANCE CHARACTERISTICS
–100
–200
–300
–400
400
300
200
100
1.7
1.5
1.3
1.1
0.9
0.7
0.5
14
12
10
8
6
4
2
0
0
0
0
0
Supply Current vs
Full-Scale Voltage
Inverting Input Bias Current
vs Null Voltage
Positive Output Saturation
Voltage vs Load Current
T
NULL VOLTAGE, REFERENCED TO V
V
INTERNAL RESISTORS
V
A
V
V
S
S
S
FS
= 25°C
= ±5V
= 5V
= ±5V
50
= 2.5V
0.5
FULL-SCALE VOLTAGE, V
10
LOAD CURRENT (mA)
T
100
T
A
T
T
A
A
= – 55 C,
A
= 25 C
1.0
= –55°C
T
= 125°C
A
= –55°C
150
20
T
A
1.5
T
= 125 C
A
200
= 25°C
FS
30
T
W
A
2.0
(V)
= 125°C
250
–
1251/56 G20
1251/56 G23
1251/56 G26
(mV)
U
300
2.5
40
–100
–150
–200
200
150
100
–50
3.0
2.5
2.0
1.5
1.0
0.5
14
12
10
50
8
6
4
2
0
0
0
Supply Current vs
Full-Scale Current
0
0
Inverting Input Bias Current
vs Null Voltage
Negative Output Saturation
Voltage vs Load Current
V
V
NULL VOLTAGE, REFERENCED TO V
V
V
V
S
C
S
FS
S
20
= 5V
= 0V
= ±5V
= ±5V
100
FULL-SCALE CURRENT, I
= 1.25V
T
–10
A
40
= 125°C
LOAD CURRENT (mA)
60
200
T
A
T
A
= 25°C
–20
80
= –55°C
T
300
A
T
T
A
100 120
= 125 C
A
= – 55 C
= 25°C
FS
–30
( A)
T
T
400
A
A
= 125°C
= –55°C
–
1251/56 G27
1251/56 G21
140 160
(mV)
1251/56 G24
500
–40
V
V
V
V
+
+
–
–
–400
–350
–300
–250
–200
–150
–100
– 2
– 1
+ 2
+1
–50
V
V
60
50
40
30
+
–
–50
0
–50
Input Common Mode Range
vs Temperature
Output Short-Circuit Current
vs Temperature
Control and Full-Scale Amp Input
Bias Current vs Input Voltage
0
–25
–25
T
T
T
A
A
A
LT1251/LT1256
= 25°C
= –55°C
= 125°C
1
0
0
TEMPERATURE ( C)
TEMPERATURE (°C)
INPUT VOLTAGE (V)
25
2
25
50
50
3
75
75
V
S
4
100
1251/56 G22
100
1251/56 G28
±7.5V
1251/56 G25
7
125
125
5