LT1013AMH Linear Technology, LT1013AMH Datasheet - Page 7

• Manufacturer Part Number: LT1013AMH
• Description: Quad Precision Op Amp
• Manufacturer: Linear Technology

APPLICATIONS
Single Supply Operation
The LT1013/1014 are fully specified for single supply
operation, i.e., when the negative supply is 0V. Input
common-mode range includes ground; the output swings
within a few millivolts of ground. Single supply operation,
however, can create special difficulties, both at the input
and at the output. The LT1013/LT1014 have specific
circuitry which addresses these problems.
At the input, the driving signal can fall below 0V— inad-
vertently or on a transient basis. If the input is more than
TYPICAL PERFORMANCE CHARACTERISTICS
–10
–20
–30
–40
40
30
20
10
TIME FROM OUTPUT SHORT TO GROUND (MINUTES)
0
Output Short Circuit Current
vs Time
0
–10
20
10
0
0.1
Gain, Phase vs Frequency
1
GAIN
U
–55 C
125 C
125 C
–55 C
25 C
25 C
0.3
5V, 0V
15V
FREQUENCY (MHz)
PHASE
INFORMATION
2
U
W
V
1
S
5V, 0V
= 15V
15V
U
W
3
3
T
V
C
A
CM
L
= 25 C
= 100pF
= 0V
100k
10M
1M
100
10
Voltage Gain vs Load
Resistance
80
100
120
140
160
180
200
U
LOAD RESISTANCE TO GROUND ( )
1k
a few hundred millivolts below ground, two distinct prob-
lems can occur on previous single supply designs, such as
the LM124, LM158, OP-20, OP-21, OP-220, OP-221, OP-
420:
a) When the input is more than a diode drop below ground,
unlimited current will flow from the substrate (V
nal) to the input. This can destroy the unit. On the LT1013/
1014, the 400
schematic diagram), protect the devices even when the
input is 5V below ground.
V
O
T
T
= 10V WITH V
T
T
T
A
A
T
A
A
A
A
= –55 C, V
= 125 C, V
= –55 C, V
= 25 C, V
= 125 C, V
= 25 C, V
V
O
WITH V
= 20mV TO 3.5V
S
S
S
S
160
140
120
100
S
S
S
= 5V, 0V
= 5V, 0V
= 5V, 0V
S
= 5V, 0V
= 15V
80
60
= 15V
= 15V
= 15V
10
Channel Separation vs
Frequency
10k
INTERACTION
LIMITED BY
THERMAL
100
resistors, in series with the input (see
–20
140
120
100
FREQUENCY (Hz)
80
60
40
20
CAPACITANCE
0
R
0.01 0.1
1k
S
Voltage Gain vs Frequency
LIMITED BY
PIN TO PIN
= 1k
V
T
V
R
S
A
IN
L
10k
= 25 C
= 15V
= 2k
LT1013/LT1014
1
= 20Vp-p to 5kHz
V
S
= 5V, 0V
R
10 100 1k 10k 100k
S
FREQUENCY (Hz)
100k
= 100
V
1M
S
= 15V
T
C
A
L
= 25 C
= 100pF
–
1M 10M
termi-
7