54abt16500 National Semiconductor Corporation, 54abt16500 Datasheet - Page 5
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54abt16500
Manufacturer Part Number
54abt16500
Description
18-bit Universal Bus Transceivers With Tri-state Outputs
Manufacturer
National Semiconductor Corporation
Datasheet
1.54ABT16500.pdf
(8 pages)
PrintDate=1998/07/14 PrintTime=11:08:55 43605 ds100225 Rev. No. 1 cmserv
Symbol
V
V
DC Electrical Characteristics
Note 7: Max number of outputs defined as (n). n − 1 data inputs are driven 0V to 3V. One output at LOW. Guaranteed, but not tested.
AC Electrical Characteristics
AC Operating Requirements
OLP
OLV
f
t
t
t
t
t
t
t
t
t
t
t
t
t
t
t
t
t
t
t
t
t
t
t
t
t
t
t
t
Symbol
Symbol
max
PLH
PHL
PLH
PHL
PLH
PHL
PZH
PZL
PHZ
PLZ
s
s
h
h
s
s
h
h
s
s
h
h
s
s
h
h
w
w
(H)
(L)
(H)
(L)
(H)
(L)
(H)
(L)
(H)
(L)
(H)
(L)
(H)
(L)
(H)
(L)
(H)
(L)
Quiet Output Maximum Dynamic V
Quiet Output Minimum Dynamic V
Maximum Clock Frequency
Propagation Delay
A or B to B or A
Propagation Delay
LEAB or LEBA to B or A
Propagation Delay
CLKAB or CLKBA to B or A
Propagation Delay
OEAB or OEBA to B or A
Propagation Delay
OEAB or OEBA to B or A
Setup Time,
A to CLKAB
Hold Time,
A to CLKAB
Setup Time,
B to CLKBA
Hold Time,
B to CLKBA
Setup Time, A to LEAB
or B to LEBA, CLK High
Hold Time, A to LEAB
or B to LEBA, CLK High
Setup Time, A to LEAB
or B to LEBA, CLK Low
Hold Time, A to LEAB
or B to LEBA, CLK Low
Pulse Width,
LEAB or LEBA, High
Parameter
Parameter
Parameter
OL
OL
Min
Min
150
1.0
1.0
1.0
1.0
1.0
1.0
1.0
1.0
1.0
1.0
4.5
4.5
4.0
4.0
1.5
1.5
1.5
1.5
4.5
4.5
1.5
1.5
3.3
3.3
T
T
0
0
0
0
5
A
A
Min
V
V
= −55˚C to +125˚C
= −55˚C to +125˚C
CC
CC
C
C
L
L
= 4.5V–5.5V
= 4.5V–5.5V
54ABT
54ABT
= 50 pF
= 50 pF
Max
-1.7
1.1
Max
Max
6.5
7.0
7.0
7.8
7.5
8.0
6.3
6.5
7.2
6.8
Units
V
V
Proof
V
5.0
5.0
CC
Units
Units
MHz
ns
ns
ns
ns
ns
ns
ns
ns
ns
ns
ns
ns
ns
ns
T
T
A
A
C
= 25˚C (Note 7)
= 25˚C (Note 7)
L
Conditions
= 50 pF; R
500
www.national.com
Figure 4
Figure 4
Figure 4
Figure 6
Figure 6
Figure 7
Figure 7
Figure 7
Figure 7
Figure 7
Figure 7
Figure 7
Figure 7
Figure 5
Fig.
Fig.
No.
No.
L
=
5