MIC4421ZM Micrel Inc, MIC4421ZM Datasheet - Page 9

IC DRIVER MOSFET 9A LS 8-SOIC

MIC4421ZM

Manufacturer Part Number
MIC4421ZM
Description
IC DRIVER MOSFET 9A LS 8-SOIC
Manufacturer
Micrel Inc
Datasheet

Specifications of MIC4421ZM

Lead Free Status
Lead free
Configuration
Low-Side
Input Type
Inverting
Delay Time
15ns
Current - Peak
9A
Number Of Configurations
1
Number Of Outputs
1
Voltage - Supply
4.5 V ~ 18 V
Operating Temperature
0°C ~ 70°C
Mounting Type
Surface Mount
Package / Case
8-SOIC (3.9mm Width)
High Side Voltage - Max (bootstrap)
-
Other names
576-1792-5
MIC4421ZM

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Part Number
Manufacturer
Quantity
Price
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MIC4421/4422
Capacitive Load Power Dissipation
Dissipation caused by a capacitive load is simply the energy
placed in, or removed from, the load capacitance by the
driver. The energy stored in a capacitor is described by the
equation:
As this energy is lost in the driver each time the load is charged
or discharged, for power dissipation calculations the 1/2 is
removed. This equation also shows that it is good practice
not to place more voltage in the capacitor than is necessary,
as dissipation increases as the square of the voltage applied
to the capacitor. For a driver with a capacitive load:
where:
f = Operating Frequency
C = Load Capacitance
V
Inductive Load Power Dissipation
For inductive loads the situation is more complicated. For
the part of the cycle in which the driver is actively forcing
current into the inductor, the situation is the same as it is in
the resistive case:
However, in this instance the R
the on resistance of the driver when its output is in the high
state, or its on resistance when the driver is in the low state,
depending on how the inductor is connected, and this is still
only half the story. For the part of the cycle when the induc-
tor is forcing current through the driver, dissipation is best
described as
where V
(generally around 0.7V). The two parts of the load dissipation
must be summed in to produce P
Quiescent Power Dissipation
Quiescent power dissipation (P
section) depends on whether the input is high or low. A low
input will result in a maximum current drain (per driver) of
≤ 0.2mA; a logic high will result in a current drain of ≤ 3.0mA.
Quiescent power can therefore be found from:
where:
August 2005
S
= Driver Supply Voltage
V
I
D = fraction of time input is high (duty cycle)
I
H
S
L
= quiescent current with input high
= quiescent current with input low
= power supply voltage
E = 1/2 C V
P
P
P
P
P
D
L
L1
L2
is the forward drop of the clamp diode in the driver
L
Q
= f C (V
= P
= V
= I
= I V
2
L1
S
R
[D I
D
+ P
O
(1 – D)
S
D
)
2
H
L2
2
+ (1 – D) I
L
Q
]
, as described in the input
O
L
required may be either
9
Transition Power Dissipation
Transition power is dissipated in the driver each time its
output changes state, because during the transition, for a
very brief interval, both the N- and P-channel MOSFETs in
the output totem-pole are ON simultaneously, and a current
is conducted through them from V
power dissipation is approximately:
where (A•s) is a time-current factor derived from the typical
characteristic curve “Crossover Energy vs. Supply Volt-
age.”
Total power (P
Definitions
P
R
P
C
P
V
P
D = Duty Cycle expressed as the fraction of time the
I
I
I
Q
O
H
D
D
S
T
L
f = Operating Frequency of the driver in Hertz
L
L
= Load Capacitance in Farads.
= Power supply current drawn by a driver when both
= Power supply current drawn by a driver when both
= Output current from a driver in Amps.
= Total power dissipated in a driver in Watts.
= Power dissipated in the driver due to the driver’s
= Power dissipated in a quiescent driver in Watts.
= Power dissipated in a driver when the output
= Output resistance of a driver in Ohms.
= Power supply voltage to the IC in Volts.
P
P
T
D
input to the driver is high.
inputs are high and neither output is loaded.
inputs are low and neither output is loaded.
load in Watts.
changes states (“shoot-through current”) in Watts.
NOTE: The “shoot-through” current from a dual
transition (once up, once down) for both drivers is
stated in Figure 7 in ampere-nanoseconds. This
figure must be multiplied by the number of repeti-
tions per second (frequency) to find Watts.
= 2 f V
= P
D
L
) then, as previously described is just
+ P
S
(A•s)
Q
+ P
T
S
to ground. The transition
M9999-081005
Micrel, Inc.

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