FSB16N0104J AVX Corporation, FSB16N0104J Datasheet - Page 4

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FSB16N0104J

Manufacturer Part Number
FSB16N0104J
Description
CAP 0.1UF 2KVDC 700VAC
Manufacturer
AVX Corporation
Series
FSBr
Datasheet

Specifications of FSB16N0104J

Capacitance
0.1µF
Voltage - Ac
700V
Voltage - Dc
2000V (2kV)
Dielectric Material
Polypropylene, Metallized
Tolerance
±5%
Esr (equivalent Series Resistance)
14.3 mOhm
Operating Temperature
-40°C ~ 85°C
Mounting Type
Chassis Mount
Package / Case
Rectangular Box
Size / Dimension
1.230" L x 0.051" W (31.10mm x 13.00mm)
Height
0.882" (22.40mm)
Termination
Screw Flange
Lead Spacing
1.083" (27.50mm)
Features
General Purpose
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
Other names
Q5182682
Medium Power Film Capacitors
FSB
STANDARDS
IEC 61071-1, IEC 61071-2: Power electronic capacitors
TANGENT OF LOSS ANGLE (TANδ
FOR POLYPROPYLENE DIELECTRIC
Polypropylene has a constant dielectric loss factor of 2x10
irrespective of temperature and frequency (up to 1 MHz).
IGBT SNUBBER
with
30
Ieff
With
=
L = stray inductance IGBT + capacitor
R = serial resistance IGBT + capacitor
b
C
0 =
b
2j
0
2
U0
b
U
I
U
0
LC
1
2
T = 1/fr
;
a
T
1
=
2L
b
R
e
–2
2
+
;
b
a
T
2
=
[
b
b
sin(2
0
2
t
t
a
b
2
T ) –
0
)
a
cos(2
-4
b
HOT SPOT TEMPERATURE CALCULATION
with
where
Due to the design of the capacitor and its technology, the
thermal impedance between the terminations and the core
of the capacitor is low, it is necessary to take care that
the capacitor is never overheated by use of wrongly sized
connections.
Do not use the capacitor as a heat sink.
Due to the complexity of the IGBT / capacitor thermal
exchanges, we recommend that thermal measurements
shall be made on the different components. We would be
pleased to advise you on specific problems.
WORKING TEMPERATURE
(according to the power to be dissipated) -40°C to +85°C
MARKING
TPC logo
Capacitance and tolerance in clear
Nominal DC voltage in clear
RMS current in clear
Date of manufacture (IEC coding)
T
θ
)
]
hot spot
+
a
1 e
P
P
Rth : Rth ambient / hot spot in °C/W
d
t
(Thermal losses) = R
(Dielectric losses) = Q x tgδ
⇒ [
= θ
–2
C
V in Volt
n
ambient
T
1
in Farad
2
+
x C
b
2
n
a
+
+ (P
x (V
a
2
d
ripple peak
+ P
I
R
a
rms
1
s
t
s
) x R
x (I
in Ampere
in Ohm
to
rms
th
peak
)
0
2
)
2
x f ] x (2 x 10
f in Hertz
θ in °C
-4
)

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