LT1673CS8#PBF Linear Technology, LT1673CS8#PBF Datasheet - Page 6

• Manufacturer Part Number: LT1673CS8#PBF
• Description: IC OPAMP R-R IN/OUT DUAL 8-SOIC
• Manufacturer: Linear Technology
• Series: Over-The-Top®r

Specifications of LT1673CS8#PBF

• Amplifier Type: General Purpose
• Number Of Circuits: 2
• Output Type: Rail-to-Rail
• Slew Rate: 0.005 V/µs
• Gain Bandwidth Product: 12kHz
• Current - Input Bias: 25pA
• Voltage - Input Offset: 200µV
• Current - Supply: 1.9µA
• Current - Output / Channel: 1.5mA
• Voltage - Supply, Single/dual (±): 2.2 V ~ 36 V, ±1.1 V ~ 18 V
• Operating Temperature: 0°C ~ 70°C
• Mounting Type: Surface Mount
• Package / Case: 8-SOIC (3.9mm Width)
• Lead Free Status / RoHS Status: Lead free / RoHS Compliant
• -3db Bandwidth: -

LT1672/LT1673/LT1674
TYPICAL PERFORMANCE CHARACTERISTICS
6
1000
–10
100
20
18
16
14
12
10
90
80
70
60
50
40
30
20
10
10
8
6
4
2
0
–400
0
100
0.1
Distribution of Input
Offset Voltage
Gain and Phase Shift
vs Frequency
Output Saturation Voltage
vs Load Current (Output Low)
V
S
–300
= 5V, 0V
INPUT OFFSET VOLTAGE ( V)
–200
T
A
1
= 85 C
LOAD CURRENT ( A)
GAIN
T
–100
FREQUENCY (Hz)
A
= – 40 C
0
10
1k
V
LT1672/73/74
5600 AMPLIFIERS
100
S
T
= 5V, 0V
A
V
200 300 400
= 25 C
100
S
PHASE
W
= 2.5V
1672/73/74 G01
1672/3/4 G07
1672/3/4 G04
U
1000
10k
120
100
80
60
40
20
0
–20
–40
–60
–80
1000
100
3.0
2.5
2.0
1.5
1.0
0.5
10
0
0.1
–40
300
200
250
150
100
Output Saturation Voltage
vs Load Current (Output High)
Supply Current vs Temperature
50
V
0
S
Noise Voltage Spectrum
1
= 5V, 0V
–20
V
S
T
= 2.5V
A
= 85 C
1
LOAD CURRENT ( A)
0
TEMPERATURE ( C)
T
A
V
FREQUENCY (Hz)
20
= – 40 C
S
= 15V
10
40
10
T
A
60
V
= 25 C
100
S
= 2.5V
1672/3/4 G05
1672/3/4 G02
80
1672/3/4 G08
1000
100
100
– 0.5
100
300
200
100
– 50
200
150
100
1.5
0.5
80
60
40
20
50
0
0
– 1
Minimum Supply Voltage
1
1
Noise Current Spectrum
Input Bias Current
vs Common Mode Voltage
V
T
V
A
S
S
0
= 85 C
= 5V, 0V
= 2.5V
1
COMMON MODE VOLTAGE (V)
TOTAL SUPPLY VOLTAGE (V)
T
A
2
2
= – 40 C
FREQUENCY (Hz)
3
T
T
4
A
A
10
= 25 C
= – 40 C
3
T
5
A
= 85 C
T
6
A
T
T
T
= 25 C
A
A
A
7
= 85 C
= 25 C
= – 40 C
4
8
1672/3/4 G09
1672/3/4 G03
1672/3/4 G06
9
100
10
5