IRU1015CT International Rectifier, IRU1015CT Datasheet - Page 5

IC REG ADJ LDO 1.5A TO-220

IRU1015CT

Manufacturer Part Number
IRU1015CT
Description
IC REG ADJ LDO 1.5A TO-220
Manufacturer
International Rectifier
Datasheet

Specifications of IRU1015CT

Regulator Topology
Positive Adjustable
Voltage - Output
2.5 ~ 3.3 V
Voltage - Input
Up to 7V
Voltage - Dropout (typical)
1.1V @ 1.5A
Number Of Regulators
1
Current - Output
1.5A
Current - Limit (min)
1.6A
Operating Temperature
0°C ~ 150°C
Mounting Type
Through Hole
Package / Case
TO-220-3 (Straight Leads)
Lead Free Status / RoHS Status
Contains lead / RoHS non-compliant
Other names
*IRU1015CT
IRU1015-CT
IRU1015-CT

Available stocks

Company
Part Number
Manufacturer
Quantity
Price
Part Number:
IRU1015CT
Manufacturer:
IR
Quantity:
6 391
Assuming the following specifications:
The steps for selecting a proper heat sink to keep the
junction temperature below 135 C is given as:
1) Calculate the maximum power dissipation using:
2) Select a package from the regulator data sheet and
3) Assuming that the heat sink is black anodized, cal-
4) With the maximum heat sink temperature calculated
5) Next, a heat sink with lower
Rev. 1.3
08/20/02
record its junction to case (or Tab) thermal resistance.
culate the maximum Heat sink temperature allowed:
Assume, ucs=0.05 C/W (heat-sink-to-case thermal
resistance for black anodized)
in the previous step, the heat-sink-to-air thermal re-
sistance (u
temperature rise above the ambient as follows:
lated in step 4 must be selected. One way to do this
is to simply look at the graphs of the "Heat Sink Temp
Rise Above the Ambient" vs. the "Power Dissipation"
and select a heat sink that results in lower tempera-
ture rise than the one calculated in the previous step.
The following heat sinks from AAVID and Thermalloy
meet this criteria.
V
V
I
T
P
P
Selecting TO-220 package gives us:
u
T
T
DT = T
DT = Temperature Rise Above Ambient
u
OUT(MAX)
JC
SA
A
S
S
IN
OUT
D
D
= 358C
= T
= 135 - 1.863(2.7 + 0.05) = 1298C
= I
= 1.23(5 - 3.45) = 1.86W
= 2.78C/W
=
= 5V
= 3.45V
OUT
J
DT
P
S
- P
= 1.2A
D
- T
3(V
SA
=
D
A
3(u
) is calculated by first calculating the
1.86
= 129 - 35 = 948C
IN
94
- V
JC
+ u
OUT
= 508C/W
CS
)
)
SA
than the one calcu-
www.irf.com
Note: For further information regarding the above com-
panies and their latest product offerings and application
support contact your local representative or the num-
bers listed below:
Designing for Microprocessor Applications
As it was mentioned before the IRU1015 is designed
specifically to provide power for the new generation of
the low voltage processors requiring voltages in the range
of 2.5V to 3.6V generated by stepping down the 5V sup-
ply. These processors demand a fast regulator that sup-
ports their large load current changes. The worst case
current step seen by the regulator is anywhere in the
range of 1 to 7A with the slew rate of 300 to 500ns which
could happen when the processor transitions from “Stop
Clock” mode to the “Full Active” mode. The load current
step at the processor is actually much faster, in the or-
der of 15 to 20ns, however, the de-coupling capacitors
placed in the cavity of the processor socket handle this
transition until the regulator responds to the load current
levels. Because of this requirement, the selection of high
frequency low ESR and low ESL output capacitor is im-
perative in the design of these regulator circuits.
Figure 5 shows the effects of a fast transient on the
output voltage of the regulator. As shown in this figure,
the ESR of the output capacitor produces an instanta-
neous drop equal to the ( V
effect will be equal to the rate of change of the output
current times the inductance of the capacitor ( V
=L3 I/ t). The output capacitance effect is a droop in
the output voltage proportional to the time it takes for
the regulator to respond to the change in the current
( V
regulator.
C
AAVID Thermalloy...............PH# (603) 528-3400
Thermalloy
= t3 I/C ) where
AAVID
6041PB
574602
0
t is the response time of the
Air Flow (LFM)
ESR
No HS Required
No HS Required
=ESR3 I) and the ESL
100
IRU1015
ESL
5

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