20CTQ045S Vishay, 20CTQ045S Datasheet - Page 3

• Manufacturer Part Number: 20CTQ045S
• Description: DIODE SCHOTTKY 45V 10A D2PAK
• Manufacturer: Vishay

Specifications of 20CTQ045S

• Voltage - Forward (vf) (max) @ If: 760mV @ 20A
• Current - Reverse Leakage @ Vr: 2mA @ 45V
• Current - Average Rectified (io) (per Diode): 10A
• Voltage - Dc Reverse (vr) (max): 45V
• Diode Type: Schottky
• Speed: Fast Recovery =< 500ns, > 200mA (Io)
• Diode Configuration: 1 Pair Common Cathode
• Mounting Type: Surface Mount
• Package / Case: D²Pak, TO-263 (2 leads + tab)
• Product: Schottky Rectifiers
• Peak Reverse Voltage: 45 V
• Forward Continuous Current: 20 A
• Max Surge Current: 1060 A
• Configuration: Dual Common Cathode
• Forward Voltage Drop: 0.76 V
• Maximum Reverse Leakage Current: 2000 uA
• Operating Temperature Range: - 55 C to + 175 C
• Mounting Style: SMD/SMT
• Lead Free Status / RoHS Status: Contains lead / RoHS non-compliant
• Reverse Recovery Time (trr): -
• Lead Free Status / RoHS Status: Contains lead / RoHS non-compliant, Lead free / RoHS Compliant
• Other names: *20CTQ045S; VS-20CTQ045S; VS-20CTQ045S; VS20CTQ045S; VS20CTQ045S

Document Number: 93952
Revision: 22-Aug-08
1000
100
Fig. 1 - Maximum Forward Voltage Drop Characteristics
10
0
0.001
0.2
0.01
0.1
10
0.00001
1
V
FM
0.4
D = 0.50
D = 0.33
D = 0.25
D = 0.17
D = 0.08
- Forward Voltage Drop (V)
0.6
(thermal resistance)
0.8
(Per Leg)
0.0001
Single pulse
1.0
Fig. 3 - Typical Junction Capacitance vs. Reverse Voltage (Per Leg)
Fig. 4 - Maximum Thermal Impedance Z
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T
T
T
1.2
J
J
J
= 175 °C
= 125 °C
= 25 °C
1000
Schottky Rectifier, 2 x 10 A
1.4
100
0.001
0
1.6
t
1
1.8
- Rectangular Pulse Duration (s)
10
V
R
- Reverse Voltage (V)
0.01
T
J
= 25 °C
20
30
thJC
0.1
0.0001
Characteristics (Per Leg)
0.001
1000
0.01
100
0.1
10
40
1
Fig. 2 - Typical Values of Reverse Current vs.
0
Vishay High Power Products
T
5
50
J
20CTQ...S/20CTQ...-1
1
= 25 °C
V
Notes:
1. Duty factor D = t
2. Peak T
T
Reverse Voltage (Per Leg)
10
R
J
= 50 °C
- Reverse Voltage (V)
T
15
J
= 75 °C
J
T
P
= P
DM
J
20
10
= 100 °C
DM
t
1
T
25
t
x Z
2
J
1
= 125 °C
/t
thJC
2
T
30
J
+ T
= 150 °C
T
C
35
J
100
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= 175 °C
40
45
3