16N78-212P.1001 Portescap Danaher Motion US LLC, 16N78-212P.1001 Datasheet - Page 8

• Manufacturer Part Number: 16N78-212P.1001
• Description: MOTOR BRUSH 16MM 6VDC
• Manufacturer: Portescap Danaher Motion US LLC
• Series: 16N78, Athlonixr
• Type: Brushed DCr

Specifications of 16N78-212P.1001

• Voltage - Rated: 6VDC
• Rpm: 9300 RPM
• Features: -
• Shaft Diameter: 0.059" (1.50mm)
• Shaft Rotational Direction: -
• Lead Free Status / Rohs Status: Lead free / RoHS Compliant
• Other names: 403-1041

through the effect of the rotor current,
particularly in the event of slow or repeated
starting. The torque M
starting-current I
M
By applying equation (1), we can calculate the
angular velocity ω produced under a voltage
U
the current required for obtaining the torque
M = M
I = M
Since M
we may also write
I = M
For the angular velocity ω, we obtain the
relationship
ω = U
In which the temperature dependence of the
rotor resistance R
in other words, the value of R
temperature of the rotor must be calculated.
On the other hand, with the eqation (6), we
can calculate the current I and the load
torque M
given voltage U
I = U
And with equation (10)
M
We get the value of M
M
The problem which most often arises is that
of determining the power supply voltage U
0
Brush DC Working Principles
d
L
L
= U
with a load torque M
= (I − I
= (I − I
= I
k
k
0
L
L
− k x ω = I
d
0
0
+ M
k
+ I
x k - M
L
k
− I x R
− R
R
+ M
f
k
0
M
k
= I
L
0
0
M
)k
)k − k
f
2
for a given angular velocity ω and a
f
0
:
(M
M
f
R
= (I
L
2
M
0
d
+ M
:
ω
− k ω
d
d
M
is obtained as follows:
R
- I
must again be considered;
f
M
)
0
)k
L
:
i
. We first determine
d
produced by the
M
at the working
(10)
(11)
(12)
(9)
0
required for obtaining a speed of rotation n
for a given load torque M
= n x 2π/60). By introducing equation (10) into
(6) we obtain:
U
Practical examples of calculations
Please note that the International System of
Units (S.I.) is used throughout.
1. Let us suppose that, for a Portescap
motor 23D21-216E, we wish to calculate the
motor constant k, the starting current I
the starting torque M
of 40°C. With a power supply voltage of 12V,
the no-load speed is n
rad/s), the no-load current I
resistance R
By introducing the values ω
the equation (8), we obtain the motor constant
k for the motor 23D21-216E:
k = 12 − 0.012 x 9.5 = 0.0232 Vs
Before calculating the starting-current, we
must calculate the rotor resistance at 40°C.
With ∆T = 18°C and R
R
The starting-current I
of 40°C becomes
I
and the starting-torque M
equation (9), is
M
2. Let us ask the following question: what is
the speed of rotation n attained by the motor
with a load torque of 0.008 Nm and a power
supply voltage of 9V at a rotor temperature
of 40°C?
d
M
0
= U
d
= M
= (1 + 0.004 x 18) = 9.5 x 1.07
= 10.2Ω
= k(I
= 0.027 Nm
R
(
0
M
k
= 12 = 1.18A
L
d
+ I
10.2
− I
0
)
0
15
) = 0.0232 (1.18 − 0.012)
R
M0
M
= 9.5 Ω at 22°C.
+ k x ω
M0
d
d
at a rotor temperature
at a rotor temperature
0
= 9.5Ω, we obtain
is 4900 rpm (ω
L
(angular velocity ω
0
0
, I
= 12 mA and the
d
, according to
0
, R
M0
and U
0
= 513
d
0
(13)
and
into
®
Using equation (10) we first calculate the
current which is supplied to the motor under
these conditions:
I = M
Equation (11) gives the angular velocity ω:
ω = U
and the speed of rotation n:
n = 60 ω = 2200 rpm
Thus the motor reaches a speed of 2200 rpm
and draws a current of 357 mA.
3. Let us now calculate the torque M at a
given speed of rotation n of 3000 rpm (ω = 314
rad/s) and a power supply voltage U
equation (12) gives the value of the current:
I = U
and the torque load M
M
(M
4. Lastly, let us determine the power supply
voltage U
rotation n of 4000 rpm (ω = 419 rad/s) with
a load torque of M
temperature again being 40°C (R
As we have already calculated, the current I
necessary for a torque of 0.008 Nm is 0.357 A
U
= 0.357A
= 1.18 − 0.0232 x 314 = 0.466A
0
L
= 231 rad/s
= I x R
= 0.357 x 10.2 + 0.0232 x 419
= 13.4 volt
L
= k(I − I
= 0.0232 (0.466 − 0.012)
= 0.0105 Nm
2π
k
= 10.5 mNm)
0
L
0
− k x ω = I
+ I
− I x R
R
k
0
M
M
= 0.008 + 0.012
+ k x ω
0
10.2
0
)
0.0232
required for obtaining a speed
M
= 9 − 0.357 x 10.2
d
− k x ω
R
M
0.0232
L
of 0.008 Nm, the rotor
L
:
M
= 10.2Ω).
0
of 15V;
.