STM32F302CCT6 STMicroelectronics, STM32F302CCT6 Datasheet - Page 127

• Manufacturer Part Number: STM32F302CCT6
• Description: ARM Microcontrollers - MCU 32-Bit ARM Cortex M4 72MHz 256kB MCU FPU
• Manufacturer: STMicroelectronics

Specifications of STM32F302CCT6

• Product Category: ARM Microcontrollers - MCU
• Rohs: yes
• Core: ARM Cortex M4
• Data Bus Width: 32 bit

STM32F302xx/STM32F303xx
7.2.2
Selecting the product temperature range
When ordering the microcontroller, the temperature range is specified in the ordering
information scheme shown in
Each temperature range suffix corresponds to a specific guaranteed ambient temperature at
maximum dissipation and, to a specific maximum junction temperature.
As applications do not commonly use the STM32F30xB/C at maximum dissipation, it is
useful to calculate the exact power consumption and junction temperature to determine
which temperature range will be best suited to the application.
The following examples show how to calculate the temperature range needed for a given
application.
Example 1: High-performance application
Assuming the following application conditions:
Thus: P
Using the values obtained in
This is within the range of the suffix 6 version parts (–40 < T
In this case, parts must be ordered at least with the temperature range suffix 6 (see
Section 8: Part
Example 2: High-temperature application
Using the same rules, it is possible to address applications that run at high ambient
temperatures with a low dissipation, as long as junction temperature T
specified range.
Assuming the following application conditions:
Thus: P
Maximum ambient temperature T
I
level with I
at low level with I
P
P
This gives: P
P
–
T
Maximum ambient temperature T
I
level with I
P
P
This gives: P
P
DDmax
DDmax
Jmax
INTmax
IOmax
Dmax
INTmax
IOmax
Dmax
Dmax
Dmax
For LQFP64, 45°C/W
= 82 °C + (45°C/W × 236.6 mW) = 82 °C + 10.65 °C = 92.65 °C
= 175 + 61.6 = 236.6 mW
= 70 + 28.8 = 98.8 mW
= 50 mA, V
= 20 mA, V
= 3 × 8 mA × 0.4 V + 2 × 20 mA × 1.3 V = 61.6 mW
= 9 × 8 mA × 0.4 V = 28.8 mW
= 236.6 mW
= 98.8 mW
= 50 mA × 3.5 V= 175 mW
= 20 mA × 3.5 V= 70 mW
OL
OL
numbering).
INTmax
INTmax
= 8 mA, V
= 8 mA, V
OL
DD
DD
= 175 mW and P
= 70 mW and P
= 20 mA, V
= 3.5 V, maximum 3 I/Os used at the same time in output at low
= 3.5 V, maximum 9 I/Os used at the same time in output at low
OL
OL
Table 79
Doc ID 023353 Rev 5
Section 8: Part
= 0.4 V and maximum 2 I/Os used at the same time in output
= 0.4 V
OL
Amax
Amax
T
= 1.3 V
Jmax
IOmax
IOmax
= 82 °C (measured according to JESD51-2),
= 115 °C (measured according to JESD51-2),
is calculated as follows:
numbering.
= 28.8 mW:
= 61.6 mW:
J
< 105 °C).
Package characteristics
J
remains within the
127/133