AD629AR Analog Devices Inc, AD629AR Datasheet - Page 13

IC AMP DIFF 25MA LDRIFT 8SOIC

AD629AR

Manufacturer Part Number
AD629AR
Description
IC AMP DIFF 25MA LDRIFT 8SOIC
Manufacturer
Analog Devices Inc
Datasheet

Specifications of AD629AR

Slew Rate
2.1 V/µs
Rohs Status
RoHS non-compliant
Design Resources
Measuring -48 V High-Side Current Using AD629, AD8603, AD780, and AD7453 (CN0100)
Amplifier Type
Differential
Number Of Circuits
1
-3db Bandwidth
500kHz
Voltage - Input Offset
200µV
Current - Supply
900µA
Current - Output / Channel
25mA
Voltage - Supply, Single/dual (±)
5 V ~ 36 V, ±2.5 V ~ 18 V
Operating Temperature
-40°C ~ 85°C
Mounting Type
Surface Mount
Package / Case
8-SOIC (3.9mm Width)
No. Of Amplifiers
1
Bandwidth
500kHz
No. Of Pins
8
Amplifier Output
Single Ended
Supply Voltage Min
2.5V
Gain Min, V/v
1
Peak Reflow Compatible (260 C)
No
Output Type
-
Gain Bandwidth Product
-
Current - Input Bias
-
Lead Free Status / RoHS Status
Contains lead / RoHS non-compliant

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ERROR BUDGET ANALYSIS EXAMPLE 2
This application is similar to the previous example except
that the sensed load current is from an amplifier with an ac
common-mode component of ±100 V (frequency = 500 Hz)
present on the shunt (see Figure 39). All other conditions are
the same as before. Note that the same kind of power-line
interference can happen as detailed in Example 1. However,
the ac common-mode component of 200 V p-p coming from
the shunt is much larger than the interference of 1 V p-p;
therefore, this interference component can be neglected.
Table 6. AD629 vs. INA117 AC Error Budget Example 2 (V
Error Source
ACCURACY, T
TEMPERATURE DRIFT (85°C)
RESOLUTION
Initial Gain Error
Offset Voltage
Gain
Offset Voltage
Noise, Typical, 0.01 Hz to 10 Hz, μV p-p
CMR, 60 Hz
Nonlinearity
AC CMR @ 500 Hz
A
= 25°C
AD629
(0.0005 × 10)/10 V × 10
(0.001 V/10 V) × 10
10 ppm/°C × 60°C
(20 μV/°C × 60°C) × 10
15 μV/10 V × 10
(141 × 10
(10
(141 × 10
-5
× 10 V)/10 V × 10
-6
-6
× 1 V)/10 V × 10
× 200 V)/10 V × 10
Rev. B | Page 13 of 16
CM
6
= ±100 V @ 500 Hz)
6
6
6
/10 V
6
6
SHUNT
6
CURRENT
1Ω
OUTPUT
Figure 39. Error Budget Analysis Example 2: V
10 AMPS
±100V AC CM
TO GROUND
INA117
(0.0005 × 10)/10 V × 10
(0.002 V/10 V) × 10
Total Accuracy Error
10 ppm/°C × 60°C
(40 μV/°C × 60°C) × 10
Total Drift Error
25 μV/10 V × 10
(500 × 10
(10
(500 × 10
Total Resolution Error
Total Error
POWER LINE
-5
60Hz
× 10 V)/10 V × 10
V
-6
-6
CM
× 1 V)/10 V × 10
× 200 V)/10 V × 10
= ±100 V at 500 Hz, R
–V
6
S
REF (–)
6
0.1µF
–IN
+IN
6
6
/10 V
6
1
2
3
4
NC = NO CONNECT
21.1kΩ
380kΩ
380kΩ
6
6
SHUNT
AD629
380kΩ
20kΩ
=1 Ω
IN
AD629
500
100
600
600
120
720
2
14
10
2820
2846
4166
= 10 V Full-Scale,
Error, ppm of FS
8
7
6
5
NC
REF (+)
AD629
INA117
500
200
700
600
240
840
3
50
10
10,000
10,063
11,603
0.1µF
V
OUT
+V
S

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