AD629AR Analog Devices Inc, AD629AR Datasheet - Page 5

• Manufacturer Part Number: AD629AR
• Description: IC AMP DIFF 25MA LDRIFT 8SOIC
• Manufacturer: Analog Devices Inc

Specifications of AD629AR

• Slew Rate: 2.1 V/µs
• Rohs Status: RoHS non-compliant
• Design Resources: Measuring -48 V High-Side Current Using AD629, AD8603, AD780, and AD7453 (CN0100)
• Amplifier Type: Differential
• Number Of Circuits: 1
• -3db Bandwidth: 500kHz
• Voltage - Input Offset: 200µV
• Current - Supply: 900µA
• Current - Output / Channel: 25mA
• Voltage - Supply, Single/dual (±): 5 V ~ 36 V, ±2.5 V ~ 18 V
• Operating Temperature: -40°C ~ 85°C
• Mounting Type: Surface Mount
• Package / Case: 8-SOIC (3.9mm Width)
• No. Of Amplifiers: 1
• Bandwidth: 500kHz
• No. Of Pins: 8
• Amplifier Output: Single Ended
• Supply Voltage Min: 2.5V
• Gain Min, V/v: 1
• Peak Reflow Compatible (260 C): No
• Output Type: -
• Gain Bandwidth Product: -
• Current - Input Bias: -
• Lead Free Status / RoHS Status: Contains lead / RoHS non-compliant

TYPICAL PERFORMANCE CHARACTERISTICS
T
A
Operating Range vs. Supply Voltage, R
Figure 6. Typical Gain Error Normalized @ V
Figure 7. Typical Gain Error Normalized @ V
Operating Range vs. Supply Voltage, R
= 25°C, V
100
–20
–20
90
80
70
60
50
40
30
20
10
Figure 5. Common-Mode Rejection Ratio vs. Frequency
0
100
–16
–16
S
V
V
= ±15 V, unless otherwise noted.
S
S
2mV/DIV
= ±18V
= ±18V
V
–12
V
–12
S
S
V
V
S
S
1k
= ±15V
= ±15V
= ±12V
= ±10V
V
V
S
S
–8
–8
= ±12V
= ±10V
–4
–4
FREQUENCY (Hz)
10k
V
V
OUT
OUT
0
0
L
(V)
(V)
L
= 10 kΩ (Curves Offset for Clarity)
= 1 kΩ (Curves Offset for Clarity)
4
4
100k
OUT
OUT
= 0 V and Output Voltage
= 0 V and Output Voltage
8
8
R
12
12
R
L
1M
L
= 10kΩ
4V/DIV
4V/DIV
= 1kΩ
16
16
20
20
10M
Rev. B | Page 5 of 16
Figure 10. Typical Gain Error Normalized @ V
Figure 9. Typical Gain Error Normalized @ V
Operating Range vs. Supply Voltage, R
Figure 8. Common-Mode Operating Range vs. Power Supply Voltage
Operating Range vs. Supply Voltage (Curves Offset for Clarity)
400
360
320
280
240
200
160
120
–20
–20
80
40
0
0
V
V
–16
S
–16
S
V
V
V
S
= ±5V, R
= ±5V, R
S
S
= ±5V, R
2
= ±2.5V, R
= ±18V
–12
–12
V
4
S
L
L
L
= ±15V
V
V
= 10kΩ
= 2kΩ
S
S
–8
= 1kΩ
–8
L
POWER SUPPLY VOLTAGE (±V)
= ±12V
= ±10V
= 1kΩ
6
–4
–4
T
8
V
V
A
OUT
OUT
= +85°C
0
0
10
(V)
(V)
L
= 2 kΩ (Curves Offset for Clarity)
4
4
OUT
OUT
12
T
A
= 0 V and Output Voltage
= +25°C
= 0 V and Output Voltage
8
8
14
12
12
R
16
L
T
4V/DIV
1V/DIV
A
= 2kΩ
= –40°C
16
16
18
AD629
20
20
20