LT3010EMS8E-5#TR Linear Technology, LT3010EMS8E-5#TR Datasheet - Page 5

IC REG LDO LIN 5V 50MA 8-MSOP

LT3010EMS8E-5#TR

Manufacturer Part Number
LT3010EMS8E-5#TR
Description
IC REG LDO LIN 5V 50MA 8-MSOP
Manufacturer
Linear Technology
Datasheet

Specifications of LT3010EMS8E-5#TR

Regulator Topology
Positive Fixed
Voltage - Output
5V
Voltage - Input
Up to 80V
Voltage - Dropout (typical)
0.3V @ 50mA
Number Of Regulators
1
Current - Output
50mA
Current - Limit (min)
60mA
Operating Temperature
-40°C ~ 125°C
Mounting Type
Surface Mount
Package / Case
8-MSOP Exposed Pad, 8-HMSOP, 8-eMSOP
Lead Free Status / RoHS Status
Contains lead / RoHS non-compliant

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Part Number
Manufacturer
Quantity
Price
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Part Number:
LT3010EMS8E-5#TRLT3010EMS8E-5
Manufacturer:
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Quantity:
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Part Number:
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Manufacturer:
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Manufacturer:
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Quantity:
20 000
Company:
Part Number:
LT3010EMS8E-5#TRPBF
0
TYPICAL PERFORMANCE CHARACTERISTICS
500
450
400
350
300
250
200
150
100
50
40
35
30
25
20
15
10
50
45
40
35
30
25
20
15
10
0
5
0
5
0
–50
0
0
Typical Dropout Voltage
Quiescent Current
LT3010 Quiescent Current
T
R
V
R
R
J
L
IN
L
L
5
–25
= 25°C
1
= ∞
= ∞, I
= 250k, I
> 6V
T
J
10
2
= 125°C
L
OUTPUT CURRENT (mA)
0
= 0 (LT3010-5)
15
3
TEMPERATURE (°C)
INPUT VOLTAGE (V)
L
= 5μA (LT3010)
T
25
J
V
V
20
SHDN
4
= 25°C
SHDN
V
V
SHDN
SHDN
25
50
5
= V
= 0V
30 35
= V
= 0V
IN
6
75
IN
7
100 125 150
40
8
30105 G01
30105 G04
30105 G07
45
9
50
10
1.295
1.290
1.285
1.280
1.275
1.270
1.265
1.260
1.255
600
500
400
300
200
100
200
180
160
140
120
100
80
60
40
20
0
0
–50
0
0
Guaranteed Dropout Voltage
LT3010 ADJ Pin Voltage
LT3010-5 Quiescent Current
I
T
R
L
J
L
= TEST POINTS
= 1mA
5
= 25°C
–25
1
= ∞
10
2
OUTPUT CURRENT (mA)
0
15
TEMPERATURE (°C)
3
INPUT VOLTAGE (V)
25
20
4
T
T
J
J
≤ 125°C
25
≤ 25°C
50
5
30
V
V
6
75
SHDN
SHDN
35
7
100
= V
= 0V
40
8
IN
125
30105 G02
30105 G05
30105 G08
45
9
150
50
10
5.08
5.06
5.04
5.02
5.00
4.98
4.96
4.94
4.92
500
450
400
350
300
250
200
150
100
2.0
1.8
1.6
1.4
1.2
1.0
0.8
0.6
0.4
0.2
50
LT3010/LT3010-5
0
0
–50
–50
0
Dropout Voltage
LT3010-5 Output Voltage
LT3010 GND Pin Current
I
L
= 1mA
1
–25
–25
2
0
0
TEMPERATURE (°C)
3
INPUT VOLTAGE (V)
TEMPERATURE (°C)
R
I
I
I
L
L
L
25
L
25
4
= 50mA
= 10mA
= 1mA
= 1.27k I
R
R
I
I
L
L
L
L
50
50
5
= 10mA*
= 50mA*
= 25.5Ω
= 127Ω
T
*FOR V
J
L
6
75
= 25°C
75
= 1mA*
7
OUT
100
100
I
R
L
L
8
= 25mA*
= 1.275V
= 51Ω
125
125
30105 G06
30105 G09
30105 G03
9
30105fd
5
150
150
10

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