ACPL-214-50AE Avago Technologies US Inc., ACPL-214-50AE Datasheet - Page 4

• Manufacturer Part Number: ACPL-214-50AE
• Description: NPN-Output Ac-Input Optocoupler,1-CHANNEL,3kV ISOLATION,SO
• Manufacturer: Avago Technologies US Inc.

Specifications of ACPL-214-50AE

• Number Of Channels: 1
• Input Type: AC, DC
• Voltage - Isolation: 3000Vrms
• Current Transfer Ratio (min): 50% @ ±1mA
• Current Transfer Ratio (max): 250% @ ±1mA
• Voltage - Output: 80V
• Current - Output / Channel: 50mA
• Current - Dc Forward (if): ±50mA
• Vce Saturation (max): 400mV
• Output Type: Transistor
• Mounting Type: Surface Mount
• Package / Case: SO-4
• Lead Free Status / RoHS Status: Lead free / RoHS Compliant

Electrical Specifications
Over recommended ambient temperature at 25ºC unless otherwise specified.
Figure 1. Switching Time Test Circuit
Figure 2. Frequency Response Test Circuit
4
I
F
Parameter
Forward Voltage
Terminal Capacitance
Collector Dark Current
Collector-Emitter Breakdown
Voltage
Emitter-Collector Breakdown
Voltage
Current Transfer Ratio
Saturated CTR
Collector-Emitter Saturation
Voltage
Isolation Resistance
Floating Capacitance
Cut-off Frequency (-3dB)
Response Time (Rise)
Response Time (Fall)
Turn-on Time
Turn-off Time
Turn-ON Time
Storage Time
Turn-OFF Time
Common Mode Rejection
Voltage
R
D
R
L
V
V
CC
CE
R
L
Symbol
V
C
I
BV
BV
CTR
CTR
V
Riso
C
F
t
t
t
t
t
T
t
CMR
CEO
r
f
on
off
ON
OFF
Output
C
S
F
t
CE
F
V
V
CEO
ECO
(sat)
(sat)
I
I
CE
CE
V
F
F
CC
Min.
-
-
-
80
7
20
-
-
5x10
-
-
-
-
-
-
-
-
-
-
t
t
on
on
10
t
t
r
r
Typ.
1.2
60
-
-
-
-
100
-
1x10
0.8
80
2
3
3
3
2
25
40
10
t
t
t
t
t
t
f
f
s
s
off
off
11
Max.
1.4
-
100
-
-
400
-
0.4
-
1
-
-
-
-
-
-
-
-
-
90%
90%
10%
10%
Units
V
pF
nA
V
V
%
%
V
:
pF
kHz
Ps
Ps
Ps
Ps
Ps
Ps
Ps
kV/Ps
Test Conditions
I
V = 0, f = 1MHz
V
I
I
I
I
I
DC500V, R.H. 40~60%
V = 0, f = 1MHz
V
R
V
R
VCC = 5V, I
R
Ta=25ºC, R
V
V
F
C
E
F
F
F
L
L
L
CE
CC
CC
CM
CC
= ±20mA
= 100 PA, I
= ±1 mA, V
= ±1mA, V
= ±8mA, I
= 0.5 mA, I
= 100:
= 100:
= 1.9k:
=9V, V
= 48V, I
= 5V, I
= 10V, I
=1.5kV(peak), I
np
C
F
L
F
C
=470:,
C
= 2 mA,
=100mV
= 16 mA,
CE
= 0 mA
F
F
CE
= 2 mA,
= 2.4mA
= 0 mA
= 0 mA
= 0.4V
= 5V
F
=0mA,
Note
Fig.6
Fig.12
CTR=(I
100%
Fig.14
Fig. 2,19
Fig. 1
Fig. 1, 17
Fig.20
C
/I
F
)x