LM4854LD National Semiconductor, LM4854LD Datasheet - Page 9

• Manufacturer Part Number: LM4854LD
• Manufacturer: National Semiconductor

Specifications of LM4854LD

• Operational Class: Class-AB
• Audio Amplifier Function: Headphone/Speaker
• Total Harmonic Distortion: 0.3@32Ohm@50mW%
• Single Supply Voltage (typ): 3/5V
• Dual Supply Voltage (typ): Not RequiredV
• Power Supply Requirement: Single
• Rail/rail I/o Type: No
• Power Supply Rejection Ratio: 71dB
• Single Supply Voltage (min): 2.4V
• Single Supply Voltage (max): 5.5V
• Dual Supply Voltage (min): Not RequiredV
• Dual Supply Voltage (max): Not RequiredV
• Operating Temp Range: -40C to 85C
• Operating Temperature Classification: Industrial
• Mounting: Surface Mount
• Pin Count: 14
• Package Type: LLP
• Lead Free Status / Rohs Status: Not Compliant

External Components Description
Typical Performance Characteristics
Components
See Figure 1.
1.
2.
3.
4.
5.
C
C
R
R
C
B
s
i
i
f
V
V
DD
DD
This is the inverting input resistance that, along with R
input capacitance C
This is the input coupling capacitor. It blocks DC voltage at the amplifier’s inverting input. C
highpass filter. The filter’s cutoff frequency is f
SELECTING EXTERNAL COMPONENTS, for an explanation of determining C
This is the feedback resistance that, along with R
The supply bypass capacitor. Refer to the POWER SUPPLY BYPASSING section for information about
properly placing, and selecting the value of, this capacitor.
This capacitor filters the half-supply voltage present on the BYPASS pin. Refer to the Application
Information section, SELECTING EXTERNAL COMPONENTS, for information about properly placing, and
selecting the value of, this capacitor..
THD+N vs Frequency
THD+N vs Frequency
= 5V, R
P
= 5V, R
P
OUT
OUT
LM4854LD
= 1000mW
= 400mW
L
L
= 4Ω (BTL),
= 8Ω (BTL),
i
form a high pass filter. The filter’s cutoff frequency is f
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Functional Description
9
c
= 1/2πR
i
, sets the closed-loop gain.
f
, sets the closed-loop gain. Input resistance R
i
C
i
. Refer to the Application Information section,
V
V
DD
DD
THD+N vs Frequency
THD+N vs Frequency
= 5V, R
= 5V, R
P
P
OUT
OUT
LM4854LD
= 400mW
c
= 50mW
L
L
= 1/2πR
= 4Ω (BTL),
= 16Ω (SE),
i
’s value.
i
C
i
.
i
and R
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i
create a
i
and