AD8170ARZ Analog Devices Inc, AD8170ARZ Datasheet - Page 7

IC MUX SW W/AMP 250MHZ 8-SOIC

AD8170ARZ

Manufacturer Part Number
AD8170ARZ
Description
IC MUX SW W/AMP 250MHZ 8-SOIC
Manufacturer
Analog Devices Inc
Datasheet

Specifications of AD8170ARZ

Applications
Multiplexer with Amplifier
Voltage - Supply
±4 V ~ 6 V
Package / Case
8-SOIC (3.9mm Width)
Mounting Type
Surface Mount
No. Of Circuits
1
Supply Current
11mA
Supply Voltage Range
± 4V To ± 6V
Operating Temperature Range
-40°C To +85°C
Analog Switch Case Style
SOIC
No. Of Pins
8
Multiplexer Configuration
2
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
Interface
-
Lead Free Status / RoHS Status
Lead free / RoHS Compliant, Lead free / RoHS Compliant

Available stocks

Company
Part Number
Manufacturer
Quantity
Price
Part Number:
AD8170ARZ
Manufacturer:
Analog Devices Inc
Quantity:
135
Part Number:
AD8170ARZ
Manufacturer:
ADI/亚德诺
Quantity:
20 000
REV. 0
Figure 17. Input & Output Impedance vs. Frequency
Figure 18. Power Supply Rejection vs. Frequency
Figure 16. Harmonic Distortion vs. Frequency
–120
–100
–110
31.6k
3.16k
316k
100k
–10
–20
–30
–40
–50
–60
–70
–80
–30
–40
–50
–60
–70
–80
–90
31.6
10k
316
100
1M
0.03
1k
10
0
0.03
0.5
(G = +1)
(OR SHUTDOWN)
OUTPUT IMPEDANCE
DISABLED
ENABLE, SD = LOGIC 1; G = +2
DISABLED (OR SHUTDOWN)
OUTPUT IMPEDANCE (G= +2)
ENABLED OUTPUT IMPEDANCE (G = +2)
ENABLE, SD = LOGIC 0, R
V
G = +2
R
R
R
V
G = +2
R
R
R
OUT
F
F
L
IN
F
F
L
= 499 (AD8170R)
= 549 (AD8174R)
= 100
0.1
= 499 (AD8170R)
= 549 (AD8174R)
= 100
0.1
= 200mV rms
1
= 2V p-p
3RD HARMONIC
2ND HARMONIC
–PSRR
FREQUENCY – MHz
1
FREQUENCY – MHz
FREQUENCY – MHz
1
ENABLED
(OR DISABLED)
INPUT
IMPEDANCE
+PSRR
S(OUT)
= 50
10
10
10
V
G = +2
R
R
*WORST CHANNEL
IN
F
F
= 499 (AD8170R)
= 549 (AD8174R)
= +0.221V rms
ENABLE,
SD = LOGIC 1;
G = +1
100
100
500
100
500
–7–
Figure 19. Frequency Response vs. Capacitive Load, G = +2
Figure 21. Open-Loop Transresistance and Phase
vs. Frequency
100k
10k
100
+0.1
–0.1
–0.3
–0.4
–0.5
–0.1
–0.2
–0.3
–0.4
–0.2
Figure 20. Small Signal Frequency Response
1M
0.1
1k
10
0
0
1k
1M
1M
V
G = +2
R
R
OUT
F
S(OUT)
C
V
G = +2
R
R
R
L
IN
F
F
L
= 1k
= 300pF
= 499 (AD8170R)
= 549 (AD8174R)
= 100
= 50mV rms
= 2V p-p
10k
= 20
PHASE
C
C
L
L
= 50pF
100k
10M
= 300pF
10M
100pF
C
FREQUENCY – Hz
FREQUENCY – Hz
FREQUENCY – Hz
L
=
1M
100pF
C
AD8170/AD8174
L
=
TRANSIMPEDANCE
100M
10M
100M
C
L
= 20pF
100M
C
50pF
L
=
C
L
= 0
1G
1G
1G
180
135
90
45
0
–45
0
–1
–2
–3
–4
–5
–6
–7
–8
–9
0
–1
–2
–3
–4
–5
–6
–7
–8
–9

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