ISL43840 Intersil Corporation, ISL43840 Datasheet - Page 11

• Manufacturer Part Number: ISL43840
• Description: Low-Voltage/ Single and Dual Supply/ Dual 4 to 1 Multiplexer Analog Switch with Enable
• Manufacturer: Intersil Corporation

Leakage Considerations
Reverse ESD protection diodes are internally connected
between each analog-signal pin and both V+ and V-. One
of these diodes conducts if any analog signal exceeds V+
or V-.
Virtually all the analog leakage current comes from the ESD
diodes to V+ or V-. Although the ESD diodes on a given
signal pin are identical and therefore fairly well balanced,
they are reverse biased differently. Each is biased by either
Typical Performance Curves
400
300
200
100
225
200
175
150
125
100
160
140
120
100
100
FIGURE 11. ON RESISTANCE vs SWITCH VOLTAGE
70
60
50
40
30
20
FIGURE 9. ON RESISTANCE vs SUPPLY VOLTAGE
80
60
90
80
70
60
50
40
75
0
2
0
25
-40
o
3
C
85
o
C
o
85
C
4
o
1
25
C
o
C
5
6
2
11
V
V- = -5V
V+ = 5V
V- = 0V
COM
V+ (V)
7
(V)
85
25
-40
8
3
o
o
V- = 0V
o
C
C
85
-40
C
25
T
o
o
85
o
25
-40
A
9
C
C
C
V
I
COM
o
= 25
o
COM
o
C
C
C
I
10
COM
4
-40
o
= 1mA
= (V+) - 1V
V+ = 2.7V
C, Unless Otherwise Specified
V- = 0V
V+ = 3.3V
V- = 0V
o
= 1mA
C
11
12
5
ISL43840
V+ or V- and the analog signal. This means their leakages
will vary as the signal varies. The difference in the two diode
leakages to the V+ and V- pins constitutes the analog-signal-
path leakage current. All analog leakage current flows
between each pin and one of the supply terminals, not to the
other switch terminal. This is why both sides of a given
switch can show leakage currents of the same or opposite
polarity. There is no connection between the analog signal
paths and GND.
120
110
100
90
80
70
60
50
90
80
70
60
50
40
30
60
50
40
30
20
60
55
50
45
40
35
30
25
20
FIGURE 10. ON RESISTANCE vs SWITCH VOLTAGE
FIGURE 12. ON RESISTANCE vs SWITCH VOLTAGE
-5
0
I
COM
25
-40
o
-4
C
o
C
= 2mA
-40
25
85
2
o
o
o
-3
C
C
C
85
-2
o
C
4
-1
V
V
25
COM
COM
o
6
0
C
V+ = 12V
V- = 0V
(V)
85
(V)
o
1
C
8
85
25
-40
2
V
o
o
o
S
C
C
I
-40
C
COM
=
3
±
o
10
5V
C
V
V
= 1mA
S
S
=
=
4
±
±
2V
3V
12
5