el5193a Intersil Corporation, el5193a Datasheet - Page 15
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el5193a
Manufacturer Part Number
el5193a
Description
Single 300mhz Current Feedback Amplifier With Enable
Manufacturer
Intersil Corporation
Datasheet
1.EL5193A.pdf
(19 pages)
Available stocks
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Part Number
Manufacturer
Quantity
Price
Part Number:
el5193aCS
Manufacturer:
EL
Quantity:
20 000
As supply voltages continue to decrease, it becomes
necessary to provide input and output voltage ranges that
can get as close as possible to the supply voltages. The
EL5193 has an input range which extends to within 2V of
either supply. So, for example, on +5V supplies, the EL5193
has an input range which spans ±3V. The output range of
the EL5193 is also quite large, extending to within 1V of the
supply rail. On a ±5V supply, the output is therefore capable
of swinging from -4V to +4V. Single-supply output range is
larger because of the increased negative swing due to the
external pull-down resistor to ground.
Video Performance
For good video performance, an amplifier is required to
maintain the same output impedance and the same
frequency response as DC levels are changed at the output.
This is especially difficult when driving a standard video load
of 150:, because of the change in output current with DC
level. Previously, good differential gain could only be
achieved by running high idle currents through the output
transistors (to reduce variations in output impedance.)
These currents were typically comparable to the entire 4mA
supply current of each EL5193 amplifier. Special circuitry
has been incorporated in the EL5193 to reduce the variation
of output impedance with current output. This results in dG
and dP specifications of 0.03% and 0.04°, while driving
150: at a gain of 2.
Video performance has also been measured with a 500:
load at a gain of +1. Under these conditions, the EL5193 has
dG and dP specifications of 0.03% and 0.04°.
Output Drive Capability
In spite of its low 4mA of supply current, the EL5193 is
capable of providing a minimum of ±95mA of output current.
With a minimum of ±95mA of output drive, the EL5193 is
capable of driving 50: loads to both rails, making it an
excellent choice for driving isolation transformers in
telecommunications applications.
Driving Cables and Capacitive Loads
When used as a cable driver, double termination is always
recommended for reflection-free performance. For those
applications, the back-termination series resistor will
decouple the EL5193 from the cable and allow extensive
capacitive drive. However, other applications may have high
capacitive loads without a back-termination resistor. In these
applications, a small series resistor (usually between 5: and
50:) can be placed in series with the output to eliminate
most peaking. The gain resistor (R
make up for any gain loss which may be created by this
additional resistor at the output. In many cases it is also
possible to simply increase the value of the feedback
resistor (R
F
) to reduce the peaking.
15
G
) can then be chosen to
EL5193, EL5193A
Current Limiting
The EL5193 has no internal current-limiting circuitry. If the
output is shorted, it is possible to exceed the Absolute
Maximum Rating for output current or power dissipation,
potentially resulting in the destruction of the device.
Power Dissipation
With the high output drive capability of the EL5193, it is
possible to exceed the 125°C Absolute Maximum junction
temperature under certain very high load current conditions.
Generally speaking when R
important to calculate the maximum junction temperature
(T
voltages, load conditions, or package type need to be
modified for the EL5193 to remain in the safe operating area.
These parameters are calculated as follows:
where:
PD
where:
PD
JMAX
T
T
n = Number of amplifiers in the package
PD
the package
V
I
V
R
SMAX
MAX
JA
MAX
MAX
S
OUTMAX
L
MAX
= Load resistance
= Supply voltage
= Thermal resistance of the package
) for the application to determine if power supply
for each amplifier can be calculated as follows:
= Maximum ambient temperature
=
= Maximum supply current of 1A
= Maximum power dissipation of each amplifier in
2
T
= Maximum output voltage (required)
u
JMAX
V
S
u
I
=
SMAX
T
MAX
+
L
+
falls below about 25:, it is
T
V
JA
S
- V
u
n
OUTMAX
u
PD
MAX
u
V
--------------------------- -
OUTMAX
R
L