LTC6404CUD-1-PBF LINER [Linear Technology], LTC6404CUD-1-PBF Datasheet - Page 15

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LTC6404CUD-1-PBF

Manufacturer Part Number
LTC6404CUD-1-PBF
Description
600MHz, Low Noise, High Precision Fully Differential Input/Output Amplifi er/Driver
Manufacturer
LINER [Linear Technology]
Datasheet
LTC6404-4 TYPICAL PERFORMANCE CHARACTERISTICS
–120
–130
–100
–110
–50
–60
–70
–80
–10
–15
–10
–15
–20
–25
–40
–90
20
15
10
–5
20
15
10
–5
5
0
5
0
0.1
10
10
Small-Signal Frequency Response
vs Gain Setting Resistor Values
Small-Signal Frequency
Response vs Temperature
Distortion vs Frequency
V
R
V
V
V
V
V
V
R
UNFILTERED DIFFERENTIAL
HD3
CM
I
S
HD2
HD2
CM
S
CM
S
OUT
I
= 100Ω, R
= 3V
= 100Ω, R
= 3V AND V
= 3V
R
= V
= V
= V
DIFFERENTIAL INPUT
SINGLE-ENDED INPUT
= 2V
I
V
V
= 140Ω, R
HD3
OCM
OCM
DIFFERENTIAL OUTPUT
OCM
S
S
P-P
= 3V
= 5V
OUTPUT AT 25°C
= MID-SUPPLY
FREQUENCY (MHz)
= MID-SUPPLY
FREQUENCY (MHz)
F
FREQUENCY (MHz)
= MID-SUPPLY
F
1
= 402Ω
S
= 402Ω
R
= 5V
I
F
= 200Ω, R
= 562Ω
100
100
FILTERED
R
T
T
I
A
A
= 100Ω, R
= 25°C
= –45°C
10
F
T
= 800Ω
A
= 90°C
F
= 402Ω
64044 G16
64044 G10
64044 G13
1000
1000
100
–100
–120
–110
–0.5
–1.0
–1.5
–2.0
–2.5
–80
–10
–15
–40
–50
–60
–70
–90
2.5
2.0
1.5
1.0
0.5
25
20
15
10
–5
DC COMMON MODE INPUT (AT IN
5
0
0
10
0
0
Distortion vs Input Common Mode
Voltage
Small-Signal Frequency
Response vs C
Large-Signal Step Response
V
R
V
V
V
R
f
IN
CM
S
CM
I
S
I
= 100Ω, R
= 100Ω, R
HD2
= 3V AND V
= 3V
= 10MHz
= V
= V
DIFFERENTIAL INPUT
SINGLE-ENDED INPUT
0.5
V
V
V
3
OCM
OCM
OUTDIFF
S
S
= 3V
= 5V
HD2
HD3
FREQUENCY (MHz)
= MID-SUPPLY
= MID-SUPPLY
F
F
= 402Ω
= 402Ω
S
HD3
1.0
C
= 5V
V
V
R
6
TIME (ns)
LOAD
CM
S
I
LOAD
= 100Ω, R
= 3V
100
C
= V
LOAD
V
= 5pF
INDIFF
OCM
1.5
C
9
LOAD
= 10pF
+
= MID-SUPPLY
F
AND IN
= 402Ω
= 0pF
12
2.0
64044 G14
64044 G17
64044 G11
PINS) (V)
1000
2.5
15
–0.25
–0.50
–0.75
–100
–120
–110
0.75
0.50
0.25
–10
–15
–40
–50
–60
–70
–80
–90
20
15
10
–5
5
0
0
10
0
Small-Signal Frequency
Response vs Temperature
Small-Signal Step Response
0
Distortion vs Output Amplitude
V
R
V
V
V
R
f
IN
CM
I
S
CM
S
I
= 100Ω, R
= 3V AND V
= 100Ω, R
= 3V
= 10MHz
= V
= V
DIFFERENTIAL INPUT
SINGLE-ENDED INPUT
1
OCM
3
OCM
HD2
= MID-SUPPLY
F
FREQUENCY (MHz)
= MID-SUPPLY
F
2
= 402Ω
S
V
= 402Ω
V
HD3
OUTDIFF
= 5V
V
V
R
OUTDIFF
6
TIME (ns)
CM
S
I
= 100Ω, R
= 3V
HD3
100
LTC6404
= V
3
T
V
T
(V
A
INDIFF
OCM
A
= –45°C
P-P
9
= 25°C
T
4
)
= MID-SUPPLY
F
A
HD2
= 402Ω
= 90°C
12
15
5
64044 G12
64044 G18
64044 G15
6404f
1000
15
6

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