LTC5100EUF Linear Technology, LTC5100EUF Datasheet - Page 9

• Manufacturer Part Number: LTC5100EUF
• Description: IC DRIVER VCSEL 3.2GBPS 16QFN
• Manufacturer: Linear Technology
• Type: Laser Diode Driverr

Specifications of LTC5100EUF

• Data Rate: 3.2Gbps
• Number Of Channels: 1
• Voltage - Supply: 3.135 V ~ 3.465 V
• Current - Supply: 54mA
• Current - Modulation: 12mA
• Operating Temperature: -40°C ~ 85°C
• Package / Case: 16-QFN
• Mounting Type: Surface Mount
• Lead Free Status / RoHS Status: Contains lead / RoHS non-compliant

V
TYPICAL PERFOR A CE CHARACTERISTICS
DD
62
60
58
56
54
52
50
60
50
10
1.01
1.00
0.99
0.98
0.97
40
30
20
0
= V
0
Rise and Fall Times vs I
Midpoint of Each Im_rng
Supply Current vs Modulation
Level (Excluding Laser Current)
0
Im_rng
Laser Bias Current
vs Temperature in CCC Mode
–40
DD(HS)
NORMALIZED TO UNITY AT 25 C
Ib_tc1 = Ib_tc2 = 0
0
Im_rng
Im_rng
4
–20
0
0
3
Im_rng
= 3.3V, T
1
AND Power_down_en = 0
AND Power_down_en = 1
TRANSMIT DISABLED
TRANSMIT DISABLED
TEMPERATURE ( C)
8
Im_rng
0
1
1
6
Impp (mA)
I
MPP
2
12
20
A
(mA)
= 25 C, Cml_en = 0, Lpc_en = 1, transmitter enabled, unless otherwise noted. Test circuit shown in Figure 5.
TRANSMIT
ENABLED
2
2
9
16
40
Im_rng
M
3
W
at the
12
3
3
60
20
t
t
FALL
RISE
5100 G13
5100 G16
5100 G20
U
80
15
24
48.1
48.0
47.9
47.8
47.7
47.6
47.5
47.4
1.00
0.98
0.97
1.01
0.99
60
50
40
65
55
45
–40
–40
0
Monitor Diode Current
vs Temperature in APC Mode
Supply Current vs Temperature
Rise and Fall Times
vs I
NORMALIZED TO UNITY AT 25 C
Imd_tc1 = Imd_tc2 = 0
3
MPP
–20
–20
6
for Im_rng = 3
TEMPERATURE ( C)
TEMPERATURE ( C)
0
9
0
I
MPP
Im_rng = 3
Impp = 12mA
Ib = 0.0mA
(INCLUDES SRC PIN
CURRENT REQUIRED
TO SUPPLY THE AVERAGE
MODULATION CURRENT
12
20
20
(mA)
15
t
t
40
FALL
RISE
40
18
21
60
60
24
5100 G14
5100 G17
5100 G21
80
80
27
10000
1000
1.01
1.00
0.99
0.98
0.97
100
7
6
4
1
0
8
5
3
2
–40
0
1
Laser Modulation Current
vs Temperature, Im_rng = 1
Deterministic Jitter vs I
Im_rng = 3
Modulator Output Resistance
vs Modulation Level
NORMALIZED TO UNITY AT 25 C
Im_tc1 = Im_tc2 = 0
3
–20
6
TEMPERATURE ( C)
0
9
I
Impp (mA)
MPP
12
20
LTC5100
10
(mA)
15
40
18
MPP
21
sn5100 5100fs
60
for
24
5100 G15
5100 G22
5100 G18
9
80
100
27