IR3088AMTRPBF International Rectifier, IR3088AMTRPBF Datasheet - Page 28

• Manufacturer Part Number: IR3088AMTRPBF
• Description: IC XPHASE W/FAULT DET 20L-MLPQ
• Manufacturer: International Rectifier
• Series: XPhase™r

Specifications of IR3088AMTRPBF

• Applications: Processor
• Current - Supply: 10mA
• Voltage - Supply: 8.4 V ~ 14 V
• Operating Temperature: 0°C ~ 125°C
• Mounting Type: Surface Mount
• Package / Case: 20-MLPQ
• Pin Count: 20
• Mounting: Surface Mount
• Package Type: MLPQ
• Case Length: 4mm
• Case Height: 0.88mm
• Lead Free Status / RoHS Status: Lead free / RoHS Compliant
• Other names: IR3088AMTRPBF; IR3088AMTRPBFTR

R
Bootstrap Capacitor C
Choose C
Decoupling Capacitors for Phase IC and Power Stage
Choose C
VOLTAGE LOOP COMPENSATION
Type III compensation is used for the converter with only ceramic output capacitors. The crossover frequency and
phase margin of the voltage loop can be estimated as follows.
Choose
Choose the desired crossover frequency fc (=140kHz) around fc1 estimated above, and calculate
Choose C
CURRENT SHARE LOOP COMPENSATION
The crossover frequency of the current share loop f
loop f
Choose C
θ
C
C
C
C
R
F
f
C
PHASE41
MI
C
CP
CP
FB
DRP
SCOMP
1
1
=
Page 28 of 33
=
=
=
=
=
C
90
=
10
2
4
2 (
R
. Choose the crossover frequency of current share loop f
(
π
π
(
V
PWMRMP
=
−
π
=
=
R
R
∗
I
∗
∗
=10k , R
FB
. 0
BST
VCC
A
CP1
SCOMP
FB
∗
20
−
. 0
C
R
f
65
tan(
L
V
1
C
f
65
1
CP
6 .
+
C
E
E
PWMRMP
=
=0.1uF
=47pF to reduce high frequency noise.
∗
=0.1uF, C
R
*
nF
)
R
∗
*
∗
2
R
DRP
*
. 0
R
2
3
FB
18
C
∗
G
FB
C
=22nF
PWMRMP
R
) 5
∗
1
E
L
PWMRMP
CS
2 .
)
1
DRP
R
E
∗
PHASE42
∗
=
FB
=
*
∗
V
180
C
−
∗
10
π
10
C
O
4
V
FB
R
=
π
E
DAC
3
VCCL
BST
*
FB
∗
=
2
3
∗
∗
*
=
*
V
12
140
63
∗
R
I
)
∗
(
(
f
=768 , R
162
100
162
FB
SW
*
( *
*
=0.1uF
R
°
I
*
105
V
1
O
∗
LE
*
10
I
*
V
V
=
+
*
10
−
RAMP
110
110
G
3
PWMRMP
*
=
V
V
. 1
∗
CS
−
34
O
DAC
576
2
110
9
65
)
Ω
π
∗
_
/
PHASE43
*
∗
=
) 6
ROOM
2
∗
0 (
∗
5
)
π
10
=
6 .
2 (
∗
(
. 1 (
5 .
62
=
∗
5
(
3
*
π
*
22
33
2 .
18
f
10
*
CI
10
∗
∗
nF
R
140
*
2 .
−
−
=2.80k
22
*
−
9
10
LE
105
3
. 1
*
, choose C
=
*
10
−
*
(
*
05
6
12
6
10
10
2
1 [
* )
*
*
3
7 .
*
. 9
*
−
+
3
62
−
1 [
10
CI
nF
)
100
6
* 1
. 0
2
2
+
)
)
π
6
∗
should be at least one decade lower than that of the voltage
75
∗
10
2
=
576
*
(
*
π
100
34
10
−
27
f
−
FB
*
CI
4
. 1
∗
−
3500
nF
)
*
) 3
=5.6nF
12
1
*
162
∗
10
3 .
C
2
*
( *
CI
π
E
−
−
800
12
*
9
∗
=3.5kHz
( *
∗
20
22
/
0 (
3500
V
) 6
−
*
*
O
*
5 .
. 1
10
10
∗
10
) 3
*
(
I
3
*
22
−
O
10
−
*
3
. 1
6
)]
,
. 0
*
*
05
and calculate C
−
*
10
75
3
62
F
*
/
MI
−
10
) 6
*
=
6
. 1 (
∗
. 0
6
=
62
011
33
146
)
∗
−
162
105
kHz
IR3088APbF
*
*
SCOMP
. 0
. 9
75
* 1
May 18, 2009
10
=
. 1
,
−
4
65
)
k
105
Ω
* ]
. 0
011