IR3086AMTRPBF International Rectifier, IR3086AMTRPBF Datasheet - Page 28

IC CTLR XPHASE 28-MLPQ

IR3086AMTRPBF

Manufacturer Part Number
IR3086AMTRPBF
Description
IC CTLR XPHASE 28-MLPQ
Manufacturer
International Rectifier
Series
XPhase™r
Datasheets

Specifications of IR3086AMTRPBF

Package / Case
20-MLPQ
Mounting Type
Surface Mount
Current - Supply
10mA
Voltage - Supply
8.4 V ~ 14 V
Operating Temperature
0°C ~ 125°C
Applications
Processor
Package
20-Lead MLPQ
Circuit
X-Phase Phase IC
Iout (a)
2.5A Gate Driver
Pbf
PbF Option Available
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
R
Bootstrap Capacitor C
Choose C
Decoupling Capacitors for Phase IC and Power Stage
Choose C
VOLTAGE LOOP COMPENSATION
Type III compensation is used for the converter with only ceramic output capacitors. The crossover frequency and
phase margin of the voltage loop can be estimated as follows.
Choose
Choose the desired crossover frequency fc (=140kHz) around fc1 estimated above, and calculate
Choose C
CURRENT SHARE LOOP COMPENSATION
The crossover frequency of the current share loop f
loop f
Choose C
θ
C
C
C
C
R
F
f
C
PHASE41
CP
MI
C
CP
SCOMP
FB
DRP
1
1
=
=
=
=
=
=
C
90
=
10
2
4
2 (
R
. Choose the crossover frequency of current share loop f
(
π
π
(
V
=
PWMRMP
Page 28 of 33
π
=
R
=
R
I
=10kΩ, R
. 0
FB
BST
VCC
A
CP1
SCOMP
FB
20
. 0
C
R
f
65
tan(
C
L
V
1
f
65
1
CP
6 .
+
C
E
E
PWMRMP
=0.1uF
=
=47pF to reduce high frequency noise.
=0.1uF, C
R
*
nF
)
R
*
2
R
DRP
*
. 0
R
2
3
FB
18
C
G
FB
C
=22nF
PWMRMP
R
) 5
1
E
L
PWMRMP
CS
2 .
)
1
DRP
R
E
PHASE42
=
FB
=
*
V
180
C
10
π
O
10
C
4
V
FB
R
=
π
E
DAC
3
VCCL
BST
*
FB
=
2
3
*
=
*
V
140
12
63
R
I
)
(
f
(
=768Ω, R
162
100
162
FB
SW
*
( *
*
=0.1uF
R
°
I
*
105
V
1
O
LE
*
10
I
*
V
V
=
+
*
10
RAMP
110
G
110
3
PWMRMP
*
=
V
V
. 1
CS
34
O
DAC
576
2
110
9
65
)
π
_
/
PHASE43
*
=
) 6
ROOM
2
0 (
5
)
π
10
=
6 .
2 (
(
. 1 (
5 .
62
=
5
(
3
*
π
*
22
33
2 .
18
f
10
*
10
CI
nF
R
140
*
2 .
=2.80kΩ
22
*
9
10
LE
105
3
. 1
*
, choose C
=
*
10
*
(
*
05
6
12
6
10
10
2
1 [
* )
*
*
3
7 .
*
. 9
*
+
3
62
1 [
10
CI
nF
)
100
6
* 1
. 0
2
2
+
)
)
π
6
should be at least one decade lower than that of the voltage
75
10
2
=
576
*
(
*
π
100
34
27
10
f
FB
*
CI
4
. 1
3500
nF
)
*
) 3
=5.6nF
12
1
*
162
10
3 .
C
2
*
( *
CI
π
E
800
12
*
9
=3.5kHz
( *
20
22
/
0 (
3500
V
) 6
*
*
O
*
5 .
. 1
10
10
10
) 3
*
(
I
3
*
22
O
10
*
3
. 1
6
)]
,
. 0
*
*
05
and calculate C
*
10
75
3
62
F
*
/
MI
10
) 6
*
=
6
. 1 (
. 0
6
=
62
011
33
146
)
162
105
kHz
*
*
SCOMP
. 0
. 9
75
* 1
IR3086A
10
=
. 1
,
4
65
1/31
)
k
105
/05
* ]
. 0
011

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