ALD500RA-10SEL Advanced Linear Devices Inc, ALD500RA-10SEL Datasheet - Page 12

• Manufacturer Part Number: ALD500RA-10SEL
• Description: IC ADC 17BIT 20SOIC
• Manufacturer: Advanced Linear Devices Inc

Specifications of ALD500RA-10SEL

• Number Of Bits: 17
• Power Dissipation (max): 10mW
• Voltage Supply Source: Dual ±
• Operating Temperature: 0°C ~ 70°C
• Mounting Type: Surface Mount
• Package / Case: 20-SOIC
• Lead Free Status / RoHS Status: Lead free / RoHS Compliant

Design Example 3:
1. Pick resolution of 18 bit. Total number of counts during
2. Pick t
3. Again, as shown from previous example, pick V
4. Next, we calculate C
5. Pick C
6. Select t
7. Calculate V
3. Pick V
4. Calculate, using equation (3) for C
5. Pick C
6. Pick t
7. Calculate the value for V
12
Use C
V
t
and V
INT
REF
For I
This t
and still achieve 18 bits resolution.
For I
C
In this case, use CINT = 1.0
V
is 262,144.
INT
DINT
C
REF
INT
=
IN
INT
REF
REF
INT
=
= 1.00V
INT
DINT
MAX = 2V
~
= 0.1666667 sec.
= 16.66667 msec. x 10 cycles
C
0.5 x 10
B
B
= 0.83 F
0.47 F as the closest practical value.
~
INT
= (0.1666667) x (20 x 10
< 4.0V
= 1.00V
= 2 x t
MAX = 20 A, applying equation (4),
MAX = 20 A, R
R
= (0.1) x (20 x 10
= 0.5 F
INT
and C
and C
REF
INT
= 2 x t
allows clock period of 0.5425 sec.
t
.
DINT
as shown in the previous examples
V
=
200 x 10
INT
AZ
AZ
-6
INT
INT
20x10
x 4 x 100 x 10
= 1.0 F
= 0.47 F
INT:
MAX
= 200 msec.
MAX
2
= 333.333 msec.
REF
-6
-3
.
= 100 K
-6
INT
, from equation (10):
R
(assume V
/4)
INT
=
(V
3
INT
20x10
F to keep
INT
-6
)/4
:
2
MAX = 4.0V)
INT
-6
MAX = 4V)
= 100 K
IN
Advanced Linear Devices
MAX = 2V
Design Example 4:
Objective: 5 1/2 digit + sign +over-range measurement.
1. Pick t
2. Pick V
3. Calculate C
4. Pick C
5. Select t
6. Calculate V
During Input Integrate Phase,
For V
For V
For I
(16.6667 msec. x 8 cycles)
Frequency = 1.8432 MHz
clock period = 0.5425 sec.
substituting the appropriate values:
V
total count =
B
INT
IN
REF
INT
16.276 x
245776
= 20 A, R
IN
REF
MAX = 2.00V, the input resolution is
DINT
= 4.0V, the basic resolution is
4
range =
= 133.333 msec. for 60Hz noise rejection.
=
~ = 1.005V
= C
REF
INT
= 2 x t
C
= 245776
AZ
INT
or 16.276 V/count
= (0.133333) x (20 x 10
as shown in Design Example 1,
133.333 x 10
0.5425 x 10
INT
V
= 0.67 F
t
V
.
DINT
INT
2V
INT
IN
V
ALD500RAU/ALD500RA/ALD500R
=
INT
MAX
MAX
= 266.667 msec.
20 x 10
MAX
MAX
2
-6
= 8.138 V/count
-3
.
-6
R
INT
= 100 K
-6
)/4 = 0.67 F
~