ADG602 AD [Analog Devices], ADG602 Datasheet - Page 2

• Manufacturer Part Number: ADG602
• Description: 2 ohm CMOS +-5 V/5 V, SPST SWITCHES
• Manufacturer: AD [Analog Devices]

ADG601/ADG602
DUAL SUPPLY
Parameter
ANALOG SWITCH
LEAKAGE CURRENTS
DIGITAL INPUTS
DYNAMIC CHARACTERISTICS
POWER REQUIREMENTS
NOTES
1
2
Specifications subject to change without notice.
Temperature range is as follows: B Version: –40°C to +85°C.
Guaranteed by design, not subject to production test.
Analog Signal Range
On Resistance (R
On-Resistance Flatness (R
Source OFF Leakage I
Drain OFF Leakage I
Channel ON Leakage I
Input High Voltage, V
Input Low Voltage, V
Input Current
C
t
t
Charge Injection
Off Isolation
Bandwidth –3 dB
C
C
C
I
I
ON
OFF
DD
SS
IN
S
D
D
I
INL
(OFF)
, C
, Digital Input Capacitance
(OFF)
S
or I
(ON)
INH
ON
(V
DD
)
D
INL
= 5 V
INH
S
D
(OFF)
(OFF)
, I
FLAT(ON)
S
(ON)
10%, V
–SPECIFICATIONS
2
)
SS
25
2
2.5
0.35
0.4
± 0.01
± 0.25
± 0.01
± 0.25
± 0.01
± 0.25
0.005
2
80
120
45
75
250
–60
180
50
50
145
0.001
0.001
= –5 V
o
C
B Version
10%, GND = 0 V, unless otherwise noted.)
–40
to +85
V
5.5
0.6
± 1
± 1
± 1
2.4
0.8
± 0.1
155
90
1.0
1.0
SS
o
to V
C
o
C
DD
–2–
Unit
V
Ω typ
Ω max
Ω typ
Ω max
nA typ
nA max
nA typ
nA max
nA typ
nA max
µA typ
µA max
pF typ
ns typ
ns max
ns typ
ns max
pC typ
dB typ
MHz typ
pF typ
pF typ
pF typ
µA typ
µA max
µA typ
µA max
Test Conditions/Comments
V
V
Test Circuit 1
V
V
V
Test Circuit 2
V
Test Circuit 2
V
Test Circuit 3
V min
V max
V
R
V
R
V
V
R
R
f = 1 MHz
f = 1 MHz
f = 1 MHz
V
Digital Inputs = 0 V or 5.5 V
Digital Inputs = 0 V or 5.5 V
DD
S
S
DD
S
S
S
IN
L
S
L
S
S
L
L
DD
= ± 4.5 V, I
= ± 3.3 V, I
= +4.5 V/–4.5 V, V
= +4.5 V/–4.5 V, V
= V
= 3.3 V; Test Circuit 4
= 3.3 V; Test Circuit 4
= 0 V, R
= 300 Ω, C
= 300 Ω, C
= 50 Ω, C
= 50 Ω, C
= V
= +4.5 V, V
= +5.5 V, V
= +5.5 V, V
D
INL
= +4.5 V, or –4.5 V;
or V
S
= 0 Ω, C
L
L
S
S
L
L
= 5 pF, f = 1 MHz; Test Circuit 6
= 5 pF; Test Circuit 7
INH
= –10 mA;
= –10 mA
= 35 pF
= 35 pF
SS
SS
SS
= –4.5 V
= –5.5 V
= –5.5 V
L
D
D
= 1 nF; Test Circuit 5
= –4.5 V/+4.5 V;
= –4.5 V/+4.5 V;
REV. 0