AD7477ARTZ-REEL7 Analog Devices Inc, AD7477ARTZ-REEL7 Datasheet - Page 7

• Manufacturer Part Number: AD7477ARTZ-REEL7
• Description: IC,A/D CONVERTER,SINGLE,10-BIT,CMOS,TSOP,6PIN
• Manufacturer: Analog Devices Inc

Specifications of AD7477ARTZ-REEL7

• Number Of Bits: 10
• Sampling Rate (per Second): 1M
• Data Interface: DSP, MICROWIRE™, QSPI™, Serial, SPI™
• Number Of Converters: 1
• Power Dissipation (max): 17.5mW
• Voltage Supply Source: Single Supply
• Operating Temperature: -40°C ~ 85°C
• Mounting Type: Surface Mount
• Package / Case: SOT-23-6
• Lead Free Status / RoHS Status: Lead free / RoHS Compliant
• For Use With: EVAL-AD7477CBZ - BOARD EVALUATION FOR AD7477
• Lead Free Status / RoHS Status: Lead free / RoHS Compliant

Timing Example 1
Having f
cycle time of t
this leaves t
of 250 ns for t
+ t
for t
REV. C
8
QUIET
+ t
QUIET
SDATA
SCLK
SCLK
SCLK
, satisfying the minimum requirement of 50 ns.
CS
CS
ACQ
, where t
2
ACQ
= 20 MHz and a throughput of 1 MSPS gives a
+ 12.5 (1/f
THREE-
to be 365 ns. This 365 ns satisfies the requirement
STATE
. From Figure 3, t
8
t
t
2
2
= 36 ns max. This allows a value of 204 ns
Z
1
SCLK
1
t
3
ZERO
4 LEADING ZEROS
) + t
2
2
ACQ
ZERO
ACQ
= 1 µs. With t
is comprised of 2.5 (1/f
Figure 2. AD7476A Serial Interface Timing Diagram
3
3
ZERO
t
4
12.5(1/f SCLK )
Figure 3. Serial Interface Timing Example
4
4
DB11
2
t
= 10 ns min,
6
t
CONVERT
5
t
5
CONVERT
t
DB10
7
SCLK
1/THROUGHPUT
)
–7–
13
Timing Example 2
Having f
cycle time of t
10 ns min, this leaves t
the requirement of 250 ns for t
comprised of 2.5 (1/f
allows a value of 128 ns for t
requirement of 50 ns. As in this example and with other slower
clock values, the signal may already be acquired before the
conversion is complete, but it is still necessary to leave 50 ns
minimum t
signal should be fully acquired at approximately Point C in
Figure 3.
13
B
B
DB2
14
14
t
SCLK
5
DB1
QUIET
C
= 5 MHz and a throughput of 315 kSPS gives a
AD7476A/AD7477A/AD7478A
2
15
15
+ 12.5 (1/f
between conversions. In Example 2, the
DB0
t
SCLK
ACQ
t
16
16
8
ACQ
) + t
SCLK
t
to be 664 ns. This 664 ns satisfies
8
THREE-STATE
QUIET
8
) + t
ACQ
+ t
t
t
, satisfying the minimum
. From Figure 3, t
QUIET
QUIET
QUIET
ACQ
t
1
= 3.174 µs. With t
, t
8
= 36 ns max. This
ACQ
is
2
=