AD829ARZ Analog Devices Inc, AD829ARZ Datasheet - Page 14

• Manufacturer Part Number: AD829ARZ
• Description: IC VIDEO OPAMP HS LN 8-SOIC
• Manufacturer: Analog Devices Inc

Specifications of AD829ARZ

• Slew Rate: 230 V/µs
• Applications: Voltage Feedback
• Number Of Circuits: 1
• -3db Bandwidth: 120MHz
• Current - Supply: 5.3mA
• Current - Output / Channel: 32mA
• Voltage - Supply, Single/dual (±): ±4.5 V ~ 18 V
• Mounting Type: Surface Mount
• Package / Case: 8-SOIC (0.154", 3.90mm Width)
• Gain Bandwidth: 120MHz
• Supply Voltage Range: ± 4.5V To ± 18V
• No. Of Amplifiers: 1
• Output Current: 32mA
• Amplifier Output: Single Ended
• Amplifier Type: High Speed, Low Noise
• Bandwidth: 600 MHz
• Common Mode Rejection Ratio: 120
• Current, Input Bias: 3.3 μA
• Current, Input Offset: 50 nA
• Current, Output: 32 mA
• Current, Supply: 5 mA
• Impedance, Thermal: 175 °C/W
• Package Type: SOIC-8
• Power Dissipation: 0.9 W
• Resistance, Input: 13 Kilohms
• Temperature, Operating, Range: 0 to +70 °C
• Voltage, Input: -13.8 to +14.3 V (Common-Mode)
• Voltage, Noise: 1.7 nV/sqrt Hz
• Voltage, Offset: 0.2 mV
• Voltage, Output, High: +3.6 V
• Voltage, Output, Low: -3.6 V
• Voltage, Supply: ±15 V
• Lead Free Status / RoHS Status: Lead free / RoHS Compliant
• Lead Free Status / RoHS Status: Lead free / RoHS Compliant, Lead free / RoHS Compliant

AD829
Because the closed-loop bandwidth is a function of R
C
loop gain, as shown in Figure 41. To preserve stability, the time
constant of R
<65 MHz. For example, with C
small signal bandwidth of the AD829 is 10 MHz. Figure 40
shows that the slew rate is in excess of 60 V/μs. As shown in
Figure 41, the closed-loop bandwidth is constant for gains of
−1 to −4; this is a property of the current feedback amplifiers.
Figure 40. Large Signal Pulse Response of Inverting Amplifier Using Current
V
COMP
Feedback Compensation, C
IN
Figure 41. Closed-Loop Gain vs. Frequency for the Circuit of Figure 38
Figure 39. Inverting Amplifier Connection Using Current Feedback
(see Figure 39), it is independent of the amplifier closed-
*RECOMMENDED VALUE
OF C
<7pF
≥7pF
100%
90
10
0%
–12
–15
CABLE
COAX
15
12
–3
–6
–9
50Ω
100k
9
6
3
0
50Ω
COMP
GAIN = –4
–3dB @ 8.2MHz
GAIN = –2
–3dB @ 9.6MHz
GAIN = –1
–3dB @ 10.2MHz
V
V
R
R
C
C1 = 15pF
IN
S
L
F
COMP
F
= ±15V
= 1kΩ
= 1kΩ
and C
= –30dBm
FOR C1
0pF
15pF
5V
C1*
R1
= 15pF
COMP
IN4148
1M
needs to provide a bandwidth of
COMP
Compensation
C
15pF FOR THIS CONNECTION
FREQUENCY (Hz)
COMP
= 15 pF, C1 = 15 pF R
R
COMP
F
SHOULD NEVER EXCEED
0.1μF
2
3
= 15 pF and R
AD829
–
+
C
+V
COMP
7
10M
S
–V
4
S
200ns
5
F
0.1μF
= 1 kΩ, R1 = 1 kΩ
6
F
= 1 kΩ, the
F
and
R
1kΩ
100M
L
V
OUT
Rev. H | Page 14 of 20
Figure 42 is an oscilloscope photo of the pulse response of a unity-
gain inverter that has been configured to provide a small signal
bandwidth of 53 MHz and a subsequent slew rate of 180 V/μs;
R
response as a unity-gain inverter, this using component values
of R
Figure 43. Small Signal Pulse Response of Inverting Amplified Using Current
F
Figure 42. Large Signal Pulse Response of the Inverting Amplifier Using
= 3 kΩ and C
F
Current Feedback Compensation, C
= 1 kΩ and C
100%
90
10
0%
100%
90
10
0%
Feedback Compensation, C
20mV
5V
COMP
COMP
= 1 pF. Figure 43 shows the excellent pulse
= 4 pF.
COMP
COMP
= 4 pF, R
= 1 pF, R
F
= 1 kΩ, R1 = 1 kΩ
200ns
10ns
F
= 3 kΩ, R1 = 3 kΩ