clc407 National Semiconductor Corporation, clc407 Datasheet - Page 3

• Manufacturer Part Number: clc407
• Description: Low-cost, Low-power Programmable Gain Buffer With Disable
• Manufacturer: National Semiconductor Corporation

CLC407 Typical Performance Characteristics
-40
-50
-60
-70
-80
-90
-10
-30
-50
7.0
6.0
5.0
4.0
3.0
2.0
50
30
10
0.1
Frequency Response
Frequency Response vs. V
Maximum Output Voltage vs. R
2nd & 3rd Harmonic Distortion
Output Resistance vs. Frequency
1
1
0
Phase
Phase
Gain
Gain
3rd R
100
l
= 100
V
2nd R
Frequency (MHz)
O
Frequency (MHz)
Frequency (MHz)
Frequency (MHz)
V
1
=4V
V
O
O
=4V
200
=2V
l
pp
Load ( )
= 100
10
10
V
1
pp
V
2nd R
O
pp
O
V
=2V
=0.2V
O
=1V
A
V
l
V
pp
V
O
300
= 1k
+2
O
10
=1V
pp
pp
=0.2V
A
V
pp
+2
out
A
pp
V
V
3rd R
+1
A
(A
400
o
V
= 2V
L
-1
v
A
100
100
l
10
V
= +1)
= 1k
A
pp
-1
V
+1
500
100
0
-45
-90
-135
-180
-100
-120
-45
-55
-65
-75
-85
-20
-40
-60
-80
-10
Frequency Response vs. R
Gain Flatness & Linear Phase Deviation
Frequency Response vs. V
2nd Harmonic Distortion vs. P
Forward & Reverse Isolation During Disable
1
1
0
1
Phase
Phase
Phase
Gain
Gain
Gain
10dBm = 2V
0dBm = .63V
Forward
Output Power (dBm)
Reverse
pp
pp
Frequency (MHz)
Frequency (MHz)
Frequency (MHz)
Frequency (MHz)
V
O
10
=4V
V
10
10
O
R
V
=1V
15
pp
3
L
0
O
V
=50
V
=2V
O
pp
O
=0.2V
R
=0.2V
R
L
pp
V
+
-
=50
L
(A
O
=1k
R
pp
=4V
L
V
R
L
out
pp
=100
O
V
L
=1V
=100
pp
50
= +2, R
(A
out
V
pp
v
500KHz
O
100
100
10MHz
100
50
R
5MHz
1MHz
=2V
= -1)
L
=1k
P
out
pp
30
10
f
= 250 : V
-135
0
-45
-90
-180
-315
-360
-180
-225
-270
0.20
0.15
0.10
0.05
100
-55
-65
-75
-45
-85
10
0
1
cc
100
Frequency Response vs. Capacitive Load
-10
Frequency Response vs. V
Equivalent Input Noise
3rd Harmonic Distortion vs. P
Differential Gain & Phase
1
1
1
Phase
Phase
Gain
Gain
= + 5V, R
+
-
C
C
1k
50
R
L
L
=1kpF
=1kpF
Number of 150 Loads
s
=10
50
Output Power (dBm)
Frequency (MHz)
Frequency (MHz)
P
Frequency (Hz)
V
out
2
C
L
C
O
L
10dBm = 2V
0dBm = .63V
L
10k
=5V
=10pF
Non-Inverting Current = 3pA/ Hz
= 100 unless specified)
V
=100pF
V
10
10
O
Inverting Current = 12pA/ Hz
O
V
=0.2V
C
pp
=0.2V
O
V
V
L
R
0
=5V
O
O
=100pF
V
Voltage = 5nV/ Hz
s
=2V
=2V
= 30
O
100k
pp
=1V
pp
pp
http://www.national.com
pp
pp
pp
pp
pp
3
out
Phase
C
(A
out
R
1M
L
V
s
=10pF
=100
v
O
100
500KHz
Gain
100
10MHz
5MHz
1MHz
=1V
= +2)
pp
10M
10
4
-135
-180
-135
-180
0
-45
-90
0
-45
-90
100
10
1.00
0.75
0.50
0.25
0
1