LT1185 LINER [Linear Technology], LT1185 Datasheet - Page 7

no-image

LT1185

Manufacturer Part Number
LT1185
Description
Low Dropout Regulator
Manufacturer
LINER [Linear Technology]
Datasheet

Available stocks

Company
Part Number
Manufacturer
Quantity
Price
Part Number:
LT1185
Quantity:
5 510
Part Number:
LT1185
Manufacturer:
OMRON
Quantity:
5 510
Part Number:
LT1185CQ
Manufacturer:
LT
Quantity:
5 510
Part Number:
LT1185CQ
Manufacturer:
LINEAR/凌特
Quantity:
20 000
Part Number:
LT1185CQ#PBF
Manufacturer:
ADI/亚德诺
Quantity:
20 000
Part Number:
LT1185CQ#TRPBF
Manufacturer:
LINEAR/凌特
Quantity:
20 000
Part Number:
LT1185CT
Manufacturer:
LT
Quantity:
22
Part Number:
LT1185CT
Manufacturer:
LT
Quantity:
5 510
Part Number:
LT1185CT
Manufacturer:
LINEAR/凌特
Quantity:
20 000
Part Number:
LT1185CT#06PBF
Manufacturer:
LINEAR/凌特
Quantity:
20 000
T
APPLICATIO S I FOR ATIO
T
Large output capacitors (electrolytic or solid tantalum)
will not cause the LT1185 to oscillate, but they will cause
a damped “ringing” at light load currents where the ESR
of the capacitor is several orders of magnitude lower than
the load resistance. This ringing only occurs as a result of
transient load or line conditions and normally causes no
problems because of its low amplitude ( 25mV).
Heat Sinking
The LT1185 will normally be used with a heat sink. The size
of the heat sink is determined by load current, input and
output voltage, ambient temperature, and the thermal
resistance of the regulator, junction-to-case (
LT1185 has two separate values for
transistor section, and a second, lower value for the
control section. The reason for two values is that the
power transistor is capable of operating at higher continu-
ous temperature than the control circuitry. At low power
levels, the two areas are at nearly the same temperature,
and maximum temperature is limited by the control area.
At high power levels, the power transistor will be at a
significantly higher temperature than the control area
and its maximum operating temperature will be the
limiting factor.
To calculate heat sink requirements, you must solve a
thermal resistance formula twice, one for the power
transistor and one for the control area. The lowest value
obtained for heat sink thermal resistance must be used. In
these equations, two values for maximum junction tem-
perature and junction-to-case thermal resistance are used,
as given in Electrical Specifications.
AMAX
JMAX
CHS
HS
HS
JC
P = Device dissipaton
=
= Maximum heat sink thermal resistance
= LT1185 junction-to-case thermal resistance
= Case-to-heat sink (interface) thermal
= LT1185 maximum operating junction
= (V
= Maximum ambient temperature in
(T
customers application
resistance, including any insulating washers
temperature
JMAX
IN
– V
– T
P
OUT
U U
AMAX
) (I
OUT
)
) +
JC
I
OUT
40
W
JC
CHS
(V
: one for the power
IN
.
)
U
JC
). The
Example: A commercial version of the LT1185 in the
TO-220 package is to be used with a maximum ambient
temperature of 60 C. Output voltage is 5V at 2A. Input
voltage can vary from 6V to 10V. Assume an interface
resistance of 1 C/W.
First solve for control area, where the maximum junction
temperature is 125 C for the TO-220 package, and
Next, solve for power transistor limitation, with
T
The lowest number must be used, so heat sink resistance
must be less than 4.2 C/W.
Some heat sink data sheets show graphs of heat sink
temperature rise vs power dissipation instead of listing a
value for thermal resistance. The formula for
rearranged to solve for maximum heat sink temperature
rise:
Using numbers from the previous example:
The smallest rise must be used, so heat sink temperature
rise must be less than 44 C at a power level of 10.5W.
For board level applications, where heat sink size may be
critical, one is often tempted to use a heat sink which
barely meets the requirements. This is permissible if
correct assumptions were made concerning maximum
ambient temperature and power levels. One complicating
JMAX
JC
section
transistor
HS
= 1 C/W:
HS
T
T
T
P = (10V – 5V) (2A) + 2A
HS
HS
HS
= 150 C,
=
= 125°C – 60°C
= 125 C – 60 – 10.5(1 + 1) = 44 C control
= 150 C – 60 – 10.5(3 + 1) = 48 C power
= T
150 – 60
10.5
JMAX
10.5W
– T
JC
– 3 – 1 = 4.6°C/W
= 3 C/W:
AMAX
– 1°C/W – 1°C/W = 4.2°C/W
– P(
40
JC
(10V) = 10.5W
+
CHS
)
LT1185
HS
can be
7

Related parts for LT1185