MC68020 Motorola, MC68020 Datasheet - Page 219
![no-image](/images/manufacturer_photos/0/4/459/motorola_sml.jpg)
MC68020
Manufacturer Part Number
MC68020
Description
(MC68020 / MC68EC020) MICROPROCESSORS USERS MANUAL
Manufacturer
Motorola
Datasheet
1.MC68020.pdf
(306 pages)
Available stocks
Company
Part Number
Manufacturer
Quantity
Price
Company:
Part Number:
MC68020CEH16E
Manufacturer:
Freescale Semiconductor
Quantity:
10 000
Company:
Part Number:
MC68020CEH25
Manufacturer:
XILINX
Quantity:
101
Company:
Part Number:
MC68020CEH25E
Manufacturer:
Freescale Semiconductor
Quantity:
10 000
Company:
Part Number:
MC68020CFC16E
Manufacturer:
MOT
Quantity:
190
Part Number:
MC68020CFC16E
Manufacturer:
MOTOROLA/摩托罗拉
Quantity:
20 000
Company:
Part Number:
MC68020CFC20E
Manufacturer:
FREESCALE
Quantity:
101
Company:
Part Number:
MC68020CFC25
Manufacturer:
FREESCALE
Quantity:
101
Company:
Part Number:
MC68020EH16E
Manufacturer:
Freescale Semiconductor
Quantity:
10 000
Company:
Part Number:
MC68020EH20E
Manufacturer:
Freescale Semiconductor
Quantity:
10 000
Part Number:
MC68020FC16E
Manufacturer:
MOTOROLA/摩托罗拉
Quantity:
20 000
For the first three clocks of this example, the bus controller and sequencer are both
performing tasks associated with the MOVE #1 instruction. The next three clocks (clocks
4, 5, and 6) demonstrate instruction overlap. The bus controller is performing a write to
memory as part of the MOVE #1 instruction. The sequencer, on the other hand, is
performing the ADD #2 instruction for two clocks (clocks 4 and 5) and beginning source
effective address (EA) calculations for the MOVE #3 instruction. The bus controller activity
completely overlaps the execution of the ADD #2 instruction, causing the ADD #2
attributed execution time to be zero clocks. The overlap also shortens the effective
execution time of the MOVE #3 instruction by one clock because the bus controller
completes the MOVE #1 write operation while the sequencer begins the MOVE #3 EA
calculation.
The sequencer continues the source EA calculation for one more clock period (clock 7)
while the bus controller begins a read for MOVE #3. When counting instruction execution
time in bus clocks, the MOVE #1 completes at the end of clock 6, and the execution of
MOVE #3 begins on clock 7.
Both the sequencer and bus controller continue with MOVE #3 until the end of clock 14,
when the sequencer begins to perform ADD #4. Timing for MOVE #3 continues because
the bus controller is still performing the write to the destination of MOVE #3. The bus
activity for MOVE #3 completes at the end of clock 15. The effective execution time for
MOVE #3 is nine clocks.
The one clock cycle (clock 15) when the sequencer is performing ADD #4 and the bus
controller is writing to the destination of MOVE #3 is absorbed by the execution time of
MOVE #3. This overlap shortens the effective execution time of ADD #4 by one clock,
giving it an attributed execution time of one clock.
MOTOROLA
EXECUTION TIME
INSTRUCTION
CONTROLLER
SEQUENCER
ACTIVITY
CLOCK
COUNT
CLOCK
BUS
BUS
LEGEND:
1
PERFORM
MOVE #1
BYTES n + 8
PREFETCH
PREFETCH
2
1) MOVE.L D4,(A1)+
2) ADD.L D4,D5
3) MOVE.L (A1),–(A2)
4) ADD.L D5,D6
Figure 8-3. Processor Activity for Example 1
MOVE.L D4,(A1)+
3
IDLE
(6)
4
PERFORM
WRITE TO (A1)+
ADD #2
WRITE
5
M68020 USER’S MANUAL
6
CALCULATE
SOURCE EA
MOVE #3
7
READ FROM (A1)
DESTINATION
8
READ
CALCULATE
MOVE #3
EA
9
10
MOVE.L (A1),–(A2)
BYTES n + 12
PREFETCH
PREFETCH
11
IDLE
(9)
12
13
PERFORM
MOVE #3
WRITE TO –(A2)
WRITE
14
15
PERFORM
ADD #4
16
ADD.L
D5,D6
IDLE
(1)
17
8- 5