LTC5598IUF LINER [Linear Technology], LTC5598IUF Datasheet - Page 6

• Manufacturer Part Number: LTC5598IUF
• Description: 5MHz to 1600MHz High Linearity Direct Quadrature Modulator
• Manufacturer: LINER [Linear Technology]

LTC5598
0dBm single-ended, BBPI, BBMI, BBPQ, BBMQ common-mode DC voltage V
0.8V
f
6
TYPICAL PERFORMANCE CHARACTERISTICS
NOISE
–10
–20
–30
–40
–50
10
–40
–50
–60
–70
0
PP,DIFF
I AND Q BASEBAND VOLTAGE (V
29
27
25
23
21
19
17
0.1
RF Two-Tone Power (Each Tone),
IM2 and IM3 vs Baseband Voltage
and Temperature (f
= f
Output IP3 vs RF Frequency
(P
LO Feedthrough to RF Output
vs LO Frequency (P
LO
LO
, two-tone baseband input signal = 2MHz, 2.1MHz, 0.5V
– 6MHz; unless otherwise noted. (Note 11)
f
f
f
f
= 10dBm)
RF , EACH
IM3
IM3
IM2
10
10
5V, 25°C
5.25V, 25°C
4.5V, 25°C
5V, –40°C
5V, 85°C
= f
= f
= f
LO FREQUENCY (MHz)
RF FREQUENCY (MHz)
LO
LO
LO
= f
– 2*f
+ 2*f
– f
LO
BB1
–f
BB1
BB1
BB1
– f
100
100
LO
+ f
+ f
BB2
LO
= 140MHz)
BB2
BB2
PP , DIFF , EACH TONE
= 10dBm)
5V, 25°C
5.25V, 25°C
4.5V, 25°C
5V, –40°C
5V, 85°C
1000
1000
5598 G10
5598 G16
5598 G13
1
)
–30
–40
–50
–60
–70
–80
–90
–20
–30
–40
–50
–60
–70
–10
–20
–30
–40
–50
85
80
75
70
65
60
55
10
0
I AND Q BASEBAND VOLTAGE (V
0.1
Output IP2 vs RF Frequency
(P
Image Rejection vs LO Frequency
(P
RF Two-Tone Power (Each Tone),
IM2 and IM3 vs Baseband Voltage
and Temperature (f
f
IM3
LO
LO
= f
f
= 10dBm)
= 10dBm)
IM3
10
10
LO
5V, 25°C
5.25V, 25°C
4.5V, 25°C
5V, –40°C
5V, 85°C
= f
– 2*f
RF FREQUENCY (MHz)
LO FREQUENCY (MHz)
LO
f
+ 2*f
BB1
RF , EACH
PP,DIFF
f
IM2
+ f
BB1
100
100
BB2
= f
= f
+ f
LO
LO
each tone, I&Q 90° shifted (lower side-band selection);
LO
BB2
– f
= 900MHz)
– f
CMBB
PP , DIFF , EACH TONE
BB1
BB1
5V, 25°C
5.25V, 25°C
4.5V, 25°C
5V, –40°C
5V, 85°C
– f
= 0.5V
1000
BB2
1000
V
5598 G14
5598 G17
5598 G11
CC
= 5V, EN = 5V, T
1
DC
)
–30
–40
–50
–60
–70
–80
–90
, I&Q baseband input signal = 100kHz,
–60
0
RF Two-Tone Power (Each Tone),
IM2 and IM3 vs RF Frequency
(P
10
8
6
4
2
0
LO
f
–1
–2
–3
–4
–5
IM3
Output 1dB Compression
vs RF Frequency (P
= 10dBm)
10
Voltage Gain vs RF Frequency
(P
= f
P
A
LO
f
f
LO
LO
IM2
IM3
RF FREQUENCY (MHz)
f
10
= 25ºC, f
RF , EACH
= 10dBm
10
– 2*f
= 10dBm)
= f
= f
RF FREQUENCY (MHz)
LO
LO
BB1
RF FREQUENCY (MHz)
– f
+ 2*f
= f
+ f
BB1
100
LO
RF
BB2
BB1
– f
– f
= f
100
BB1
BB2
+ f
100
5V, 25°C
5.25V, 25°C
4.5V, 25°C
5V, –40°C
5V, 85°C
LO
LO
BB2
– f
= 10dBm)
BB
1000
5V, 25°C
5.25V, 25°C
4.5V, 25°C
5V, –40°C
5V, 85°C
5598 G18
, P
1000
LO
5598 G15
1000
–40
–100
5598f
=
5598 G12