M56789 Mitsubishi, M56789 Datasheet - Page 8

• Manufacturer Part Number: M56789
• Description: 4 CHANNEL ACTUATOR DRIVER
• Manufacturer: Mitsubishi

I/O terminal equivalent circuit
(7)CH1,2,3,4 power amplifier
BASICALLY CHARACTERISTICS
Output saturation voltage and Load current characteristic.
This data is an example for typical sample.
BOOTSTRAP
(VM1(+), VM1(-), VM2(+), VM2(-),
5.0
4.0
3.0
1.0
5.0
4.0
3.0
1.0
2.0
2.0
0
0
VM3(+), VM3(-), VM4(+), VM4(-), )
CH1
CH3
Load Current (mA)
0.2
0.2
0.24v
OUTPUT terminal equivalent circuit
0.5v
0.3v
Load Current (mA)
0.22v
Vm1=V
Vm3=V
0.4 0.5
0.4 0.5
VM3+,VM3-
Vm
GND
V
CC
CC
CC
2
1=5v,V
1=5v,V
VM3+,VM3-
0.6
0.6
VM(+,-)
0.35v
CC
CC
VM1+,VM1-
2=12v
2=12v
0.8
0.8
0.46v
0.5v
VM1+
VM1-
1.0
1.0
The equivalent circuits of an output stage of the power amplifier
are shown in (7) .
The power supplies of CH1,CH2 are Vm1.
The power supply of CH3 is Vm3, and the power supply of CH4 is
Vm2.
The source side of the power amplifier output stage consists of a
PNP and a NPN. The emitta of the PNP is connected to V
the power supplies of the PNP can be adjusted externally.
[About bootstrap advantage]
The output stage of the power amplifier consists of the preceding
components. If V
Vm* (The recommendation voltage is Vm*+1V) externally, the
output range can be wider than that of V
Please take advantage of this bootstrap function for the system
which has many power supplies. And it is the same with the
external bootstrap circuit which provides V
inputs than Vm*.
Also the bootstrap can decrease the saturation voltage at the
source side of the power amplifier output stage. Therefore, when
the outputs of the power amplifiers which drive motors and
actuators are fully swung, the power dissipation of the IC will be
decreased.
5.0
4.0
3.0
1.0
5.0
4.0
3.0
1.0
2.0
2.0
0
0
CH2
CH4
MITSUBISHI <CONTROL / DRIVER IC>
0.2
0.2
CC
0.3v
0.3v
0.3v
4 CHANNEL ACTUATOR DRIVER
0.5v
2 is provided with higher voltage input than
Load Current (mA)
Load Current (mA)
Vm2=V
Vm1=V
0.4 0.5
0.4 0.5
CC
CC
VM4+,VM4-
VM4+,VM4-
1=5v,V
1=5v,V
0.6
0.6
VM2+,VM2-
0.3v
CC
CC
2=12v
2=12v
0.6v
M56789FP
CC
0.6v
0.8
0.8
CC
2=Vm*.
2 with higher voltage
VM2-
VM2+
1.0
1.0
CC
2. So