MAX15112EVKIT# Maxim Integrated, MAX15112EVKIT# Datasheet - Page 18

• Manufacturer Part Number: MAX15112EVKIT#
• Description: Power Management IC Development Tools MAX15112 Eval Kit
• Manufacturer: Maxim Integrated
• Type: Power Switchesr
• Series: MAX15112r

Specifications of MAX15112EVKIT#

• Rohs: yes
• Product: Evaluation Kits
• Tool Is For Evaluation Of: MAX15112
• Input Voltage: 2.7 V to 5.5 V
• Output Voltage: 0.6 V
• Maximum Operating Temperature: + 85 C
• Minimum Operating Temperature: - 40 C
• Output Current: 12 A
• For Use With: MAX15112

The peak current-mode controller’s modulator gain is
attenuated by the equivalent divider ratio of the load
resistance and the current-loop gain. G
where R
frequency, L is the output inductance, D is the duty cycle
(V
calculated as:
where V
The power modulator’s dominant pole is a function of the
parallel effects of the load resistance and the current-
loop gain’s equivalent impedance. Assuming that ESR
of the output capacitor is much smaller than the parallel
combination of the load and the current loop, f
be calculated as:
The power modulator zero is:
The total system transfer can be written as:
OUT
f
PMOD
High-Efficiency, 12A, Current-Mode Synchronous
G
/V
MOD
SLOPE
IN
LOAD
GAIN s
Step-Down Regulator with Integrated Switches
=
), and K
f
2
ZMOD
K
=
π ×
×
S
( )
g
= V
= 130mV and g
G
= +
MC
C
FILTER
1
=
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OUT
=
G
OUT
S
×
V
f
FF
ZESR
1
1
is the slope compensation factor
SLOPE
×
+
( )
/I
( )
s
R
s
OUT(MAX)
R
f
SW
LOAD
×
LOAD
=
×
V
G
G
IN
2
x L
×
EA
π ×
SAMPLING
f
- V
SW
MC
+
( )
×
C
s
OUT


, f
2
K
OUT
× ×
= 80A/V.
×
π ×
1
[K
L g
1
S
SW
G
×
S
MOD
f
SW
×
(1- D) - 0.5
MOD
×
( )
is the switching
MC
ESR
s
(1- D) - 0.5]
× ×
( )
DC
L C
becomes:
PMOD
OUT


can
where:
The dominant poles and zeros of the transfer loop gain
are:
The order of pole occurrence is:
where Q
G
EA
G
×
SAMPLING
sC
f
(s) 10
P2
OUT
=
G
=
C
FF
2
f
=
π ×
P1



f
(s)
AVEA(dB)/20
P1
2
π ×
π ×
<
(s)
C
<<
=
G
[K
OUT
f
R
R1 R2 sC
FILTER
f
P2
=
Z2
1
2
LOAD
sC
S
f
R2
π ×
(
Z1
+
<
π ×
×



=
OUT
R
(1- D) - 0.5]
=
1
C
f
2
f
LOAD
P3
s
Z1
(s) R
f
π ×
SW
2
×
C
×
2
+
1
π ×
ESR
sC
<
=
×
K
=
C
)
10
S
2
2
f
C R
f
g
SW
C
OUT
1
CO
sC R1 1
FF
1
+
2
1
π ×
LOAD
×
M
+
C C




AVEA(dB)/20
+
K
MAX15112
10
(1- D) - 0.5
(R1||R2) 1
1
FF
π ×
1
f
<
sC R
S
ESR
SW
AVEA(dB)/20
×
f
f
f
C C
P3
SW
SW
(1- D) - 0.5
+
×
g
s
L
M
<
×
×
+
+
Q
L
f



Z2
1
-1
C
+
+

 +


1



1
-1
1