MAX15112EVKIT# Maxim Integrated, MAX15112EVKIT# Datasheet - Page 19

• Manufacturer Part Number: MAX15112EVKIT#
• Description: Power Management IC Development Tools MAX15112 Eval Kit
• Manufacturer: Maxim Integrated
• Type: Power Switchesr
• Series: MAX15112r

Specifications of MAX15112EVKIT#

• Rohs: yes
• Product: Evaluation Kits
• Tool Is For Evaluation Of: MAX15112
• Input Voltage: 2.7 V to 5.5 V
• Output Voltage: 0.6 V
• Maximum Operating Temperature: + 85 C
• Minimum Operating Temperature: - 40 C
• Output Current: 12 A
• For Use With: MAX15112

Figure 3
totic system closed-loop response, including the domi-
nant pole and zero locations.
The loop response’s fourth asymptote (in bold,
is the one of interest in establishing the desired crossover
frequency (and determining the compensation compo-
nent values). A lower crossover frequency provides for
stable closed-loop operation at the expense of a slower
load and line-transient response. Increasing the cross-
over frequency improves the transient response at the
(potential) cost of system instability. A standard rule of
thumb sets the crossover frequency P 1/5 to 1/10 of the
switching frequency.
1) Select the desired crossover frequency. Choose f
Figure 3. Asymptotic Loop Response of Peak Current-Mode Regulator
UNITY
GAIN
equal to 1/10th of f
dB
High-Efficiency, 12A, Current-Mode Synchronous
[2 G C
NOTE:
R
*f
WHICH FOR
ESR << {R
BECOMES
f
f
PMOD
PMOD
OUT
PMOD
shows a graphical representation of the asymp-
Step-Down Regulator with Integrated Switches
C
1ST POLE
x g
(10
= 10
= [2 G C
= (2 G C
M
= [2 G C
AVEA(dB)/20
-1
AVEA(dB)/20
LOAD
)]
-1
OUT
OUT
OUT
-1
+ [K
���������������������������������������������������������������� Maxim Integrated Products 19
x {R
x R
x (ESR + {R
S
LOAD
x g
LOAD
(1 – D) – 0.5] x (L x f
2ND POLE
f
M
SW
PMOD
-1
)
-1
-1
1ST ASYMPTOTE
R2 x (R1 + R2)
+ [K
+ [K
, or f
LOAD
*
Closing the Loop: Designing
1ST ZERO
(2 G C
S
S
(1 – D) – 0.5] x (2 G C
the Compensation Circuitry
(1 – D) – 0.5] x (L x f
-1
2ND ASYMPTOTE
R2 x (R1 + R2)
+ [K
C
CO
R
C
S
)
-1
-1
(1 – D) – 0.5] x (L x f
SW
x 10
@ 100kHz.
)
-1
f
AVEA(dB)/20
CO
}
-1
-1
3RD ASYMPTOTE
R2 x (R1 + R2)
x (2 G C
x g
OUT
SW
M
)
x (2 G C
OUT
-1
x L x f
x g
}
-1
4TH ASYMPTOTE
R2 x (R1 + R2)
x (2 G C
MC
3RD POLE
]
SW
x {R
0.5 x f
-1
SW
C
)
x R
-1
-1
)
LOAD -1
-1
}
)
-1
x g
OUT
-1
LOAD
SW
Figure
x g
)]
M
-1
MC
x {R
x (2 G C
+ [K
x {1 + R
(2 G C
x R
2ND ZERO
LOAD -1
S
-1
(1 – D) – 0.5] x (L x f
LOAD
OUT
CO
C
x g
3)
)
LOAD
-1
ESR)
M
x {1 + R
x g
+ [K
x R
x [K
MC
-1
5TH ASYMPTOTE
R2 x (R1 + R2)
x [(2 G C
C
S
S
x R
(1 – D) – 0.5] x (L x f
x g
LOAD
x (1 – D) – 0.5] x (L x f
2) Select R
where K
and g
LOAD
MC
OUT
× π ×
x [K
6TH ASYMPTOTE
R2 x (R1 + R2)
x ESR x {R
gain equal to unity (assuming f
R
x R
2
x {R
x {1 + R
SW
C
S
-1
)
LOAD
M
x (1 – D) – 0.5] x (L x f
-1
R
LOAD -1
x g
becomes:
}
-1
C
f
= 1.1mS, g
S
LOAD
M
CO
)
LOAD -1
x {1 + R
-1
x R
=
is calculated as:
+ [K
-1
C
x [K
R1 R2
C
×
K
x g
SW
x g
S
SW
+ [K
(1 – D) – 0.5] x (L x f
C
S
S
LOAD
using the transfer-loop’s fourth asymptote
R2
M
MC
)
)
+
x (1 – D) – 0.5] x (L x f
-1
-1
S
OUT
x R
= +
(1 – D) – 0.5] x (L x f
}
}
x R
-1
-1
1
C
x [K
)
-1
LOAD
x g
SW
MC
×
S
MC
×
V
)
-1
x (1 – D) – 0.5] x (L x f



x {1 + R
SLOPE






x R
1
}
ESR
-1
= 80A/V, and V
+
LOAD
R
SW
LOAD
g
LOAD
V
)
x {1 + R
+
-1
M
SW
SW
IN
}
×
x [K
-1
R
)
)
×
-1
-1
)
f
-1
- V
LOAD
SW
}
}
S
g
-1
LOAD
-1
MAX15112
x (0.5 x f
x (1 – D) – 0.5] x (L x f
1
MC
×
x (0.5 f
OUT
L f
CO
K [(1- D) - 0.5]
× ×
x [K
×
SW
L g
S
×
S
SW
SW
+
> f
SW
R
SLOPE
)
x (1 – D) – 0.5] x (L x f
-1
)2 x (2 G f)
)
K [(1- D) - 0.5]
2
LOAD
}
-1
x (2 G f)
P1
S
MC
1
, f
L f
-2
-2
×
FREQUENCY
P2
= 130mV.
SW
SW
, and f
)
-1
}
-1



SW
)
-1
Z1






}
-1
).