L6258EX STMicroelectronics, L6258EX Datasheet - Page 21

IC MOTOR DRIVER UNIV 36-PWRSOIC

L6258EX

Manufacturer Part Number
L6258EX
Description
IC MOTOR DRIVER UNIV 36-PWRSOIC
Manufacturer
STMicroelectronics
Type
Driverr
Datasheet

Specifications of L6258EX

Applications
DC Motor Driver, Stepper Motor Driver
Number Of Outputs
2/1
Current - Output
1.5A
Voltage - Load
12 V ~ 40 V
Voltage - Supply
4.75 V ~ 5.25 V
Mounting Type
Surface Mount
Package / Case
PowerSO-36 Exposed Bottom Pad
Operating Supply Voltage
12 V to 40 V
Supply Current
15 mA
Mounting Style
SMD/SMT
Operating Temperature
150 C
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
Operating Temperature
-
Lead Free Status / Rohs Status
Lead free / RoHS Compliant
Other names
497-3702-5
E-L6258EX

Available stocks

Company
Part Number
Manufacturer
Quantity
Price
Part Number:
L6258EX
Manufacturer:
WOLFSON
Quantity:
1 440
Part Number:
L6258EX PBF
Manufacturer:
ST
0
Part Number:
L6258EX-1LF
Manufacturer:
ST
0
Part Number:
L6258EXTR
Manufacturer:
ST
0
Part Number:
L6258EXTR-1LF
Manufacturer:
ST
0
L6258EX
In this case the Bx block has a DC gain equal to the open loop and equal to zero at a
frequency given by the following formula:
In order to cancel the pole of the load, the zero of the Bx block must be located at the same
frequency of 163Hz; so now we have to find a compromise between the resistor and the
capacitor of the compensation network.
Considering that the resistor value defines the gain of the Bx block at the zero frequency, it
is clear that this parameter will influence the total bandwidth of the system because,
annulling the load pole with the error amplifier zero, the slope of the total transfer function is
-20dB/decade.
So the resistor value must be chosen in order to have an error amplifier gain enough to
guarantee a desired total bandwidth.
In our example we fix at 35dB the gain of the Bx block at zero frequency, so from the
formula:
where: Rb = 20kΩ
we have: Rc = 1.1MΩ
Therefore we have the zero with a 163Hz the capacitor value:
Now we have to analyse how the new Aloop transfer function with a compensation network
on the error amplifier is.
The following bode diagram shows:
the Ax function showing the position of the load pole
the open loop transfer function of the Bx block
the transfer function of the Bx with the RC compensation network on the error
amplifier
the total Aloop transfer function that is the sum of the Ax function plus the transfer
function of the compensated Bx block.
Cc
=
---------------------------------------------
Bx
Fzero
1
=
Bx_gain @ zero freq.
Fzero
------- -
Rb
Zc
Rc
=
=
=
Rc j
--------------------------------------------- -
----------------------------------- -
---------------------------------------------------------------- -
6,28
Rc
----------------------------- -
1
Rb
163
1
=
f
Cc
1
20
1,1
Cc
log
10
PWM current control loop
Rc
------- -
Rb
6
=
880pF
21/32

Related parts for L6258EX