IR3080MPBF International Rectifier, IR3080MPBF Datasheet - Page 30
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IR3080MPBF
Manufacturer Part Number
IR3080MPBF
Description
IC PHASE CONTROLLER 32MLPQ
Manufacturer
International Rectifier
Series
XPhase™r
Datasheet
1.IR3080MTRPBF.pdf
(41 pages)
Specifications of IR3080MPBF
Applications
Processor
Current - Supply
11mA
Voltage - Supply
9.5 V ~ 14 V
Operating Temperature
0°C ~ 100°C
Mounting Type
Surface Mount
Package / Case
32-MLPQ
Package
32-Lead MLPQ
Circuit
X-Phase Control IC
Switch Freq (khz)
150kHz to 1.0MHz
Pbf
PbF Option Available
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
The phase delay resistor ratios for phases 1 to 6 at 400kHz of switching frequencies are RA
RA
slope. Pre-select R
R
Bootstrap Capacitor C
Choose C
Decoupling Capacitors for Phase IC and Power Stage
Choose C
VOLTAGE LOOP COMPENSATION
Type II compensation is used for the converter with AL-Polymer output capacitors. Choose the crossover frequency
fc=40kHz, which is 1/10 of the switching frequency per phase, and determine Rcp and C
Choose C
CURRENT SHARE LOOP COMPENSATION
The crossover frequency of the current share loop f
loop f
Choose C
C
C
R
R
F
PHASE22
CP
MI
PHASE
CP
SCOMP
PHASE2
Page 30
=
=
=
C
2 (
10
12
R
. Choose the crossover frequency of current share loop f
(
V
=
PWMRMP
π
=
V
=
=
∗
I
=7.15kΩ, R
∗
O
. 0
BST
VCC
CP1
SCOMP
=0.415, RA
31
−
. 0
1
R
*
f
65
L
V
−
C
65
4 .
RA
CP
E
PWMRMP
=0.1uF
)
=47pF to reduce high frequency noise.
RA
=0.1uF, C
nF
1
*
2
∗
*
PHASE
*
+
R
∗
16
C
PHASE
C
=33nF.
2 (
PWMRMP
L
E
PWMRMP
E
2 .
π
PHASE11
1
∗
=
*
*
−
C
1
PHASE32
10
10
PHASE3
f
V
∗
E
C
DAC
3
VCCL
R
BST
∗
*
∗
*
*
*
V
PHASE
R
C
12
I
FB
)
(
f
=R
*
SW
*
220
( *
*
=0.1uF
=0.202, RA
R
∗
I
=2.55kΩ, R
105
V
11
C
O
PHASE21
V
*
I
)
V
RAMP
∗
*
2
=
−
10
G
PWMRMP
*
V
V
1
CS
34
−
O
2
DAC
−
. 0
9
=
0 .
∗
_
. 0
( *
628
/
ROOM
2
=R
) 6
∗
2 (
. 1 (
628
)
π
. 0
10
π
PHASE4
∗
35
PHASE42
∗
47
=
. 1 (
PHASE31
(
3
∗
∗
560
16
f
−
*
40
CI
*
33
10
10
20
R
2 .
*
∗
LE
−
*
∗
. 1
*
10
∗
−
10
(
=0.246, RA
10
105
12
3
10
10
*
05
=3.24kΩ, P
3
=R
3
1 [
−
6
)
−
3
6
−
2
*
* )
*
=
3
*
+
*
∗
* )
0
10
PHASE41
CI
. 9
16
10
220
2
8 .
1 [
(
* 1
220
π
6
9 .
should be at least one decade lower than that of the voltage
+
)
−
1
*
10
k
*
. 1
2
+
=
Ω
∗
10
f
π
35
CI
2 (
71
10
−
PHASE5
*
4
−
PHASE52
π
=R
)
*
nF
12
)
−
4
( *
9
∗
*
C
*
*
/
CI
PHASE51
40
10
2
12
E
) 6
, Choose C
400
π
=4kHz
( *
*
3
∗
=0.441 and RA
−
∗
10
V
*
(
. 1
4
*
560
O
=7.87kΩ, R
560
10
*
3
35
*
10
I
3
)
= R
∗
560
,
O
*
*
and calculate C
10
3
)]
10
0
*
*
−
8 .
*
. 1
PHASE61
CP
6
−
F
10
6
05
∗
MI
=
=68nF
*
10
−
. 0
6
10
*
PHASE62
)
*
10
011
∗
PHASE6
*
7
365
6
. 1 (
*
=10kΩ,
10
33
∗
−
3
0
−
=17.4kΩ
SCOMP
)
CP
8 .
=0.637 starting from down-
2
105
.
=
2
*
IR3080PbF
0 .
. 9
,
k
* 1
Ω
10
−
PHASE1
4
)
105
* ]
=0.628,
. 0
011