ISL8101IRZ Intersil, ISL8101IRZ Datasheet - Page 18

• Manufacturer Part Number: ISL8101IRZ
• Description: IC PWM CTRLR BUCK 2PHASE 24-QFN
• Manufacturer: Intersil

Specifications of ISL8101IRZ

• Applications: Controller, Intel VRM9, VRM10, and AMD Hammer Applications
• Voltage - Input: 4.6 ~ 12 V
• Number Of Outputs: 1
• Voltage - Output: 0.6 ~ 2.3 V
• Operating Temperature: -40°C ~ 85°C
• Mounting Type: Surface Mount
• Package / Case: 24-VQFN Exposed Pad, 24-HVQFN, 24-SQFN, 24-DHVQFN
• Lead Free Status / RoHS Status: Lead free / RoHS Compliant

Component Selection Guidelines
Output Capacitor Selection
The output capacitor is selected to meet both the dynamic
load requirements and the voltage ripple requirements. The
load transient a microprocessor impresses is characterized
by high slew rate (di/dt) current demands. In general,
multiple high quality capacitors of different size and dielectric
are paralleled to meet the design constraints.
Should the load be characterized by high slew rates, attention
should be particularly paid to the selection and placement of
high-frequency decoupling capacitors (MLCCs, typically
multi-layer ceramic capacitors). High frequency capacitors
supply the initially transient current and slow the load
rate-of-change seen by the bulk capacitors. The bulk filter
capacitor values are generally determined by the ESR
(effective series resistance) and capacitance requirements.
High frequency decoupling capacitors should be placed as
close to the power pins of the load, or for that reason, to any
decoupling target they are meant for, as physically possible.
Attention should be paid as not to add inductance in the
circuit board wiring that could cancel the usefulness of these
low inductance components. Consult with the manufacturer
of the load on specific decoupling requirements.
Use only specialized low-ESR capacitors intended for
switching-regulator applications for the bulk capacitors. The
bulk capacitor’s ESR determines the output ripple voltage
and the initial voltage drop following a high slew-rate
transient’s edge. In most cases, multiple capacitors of small
case size perform better than a single large case capacitor.
Bulk capacitor choices include aluminum electrolytic, OS-Con,
Tantalum and even ceramic dielectrics. An aluminum
electrolytic capacitor’s ESR value is related to the case size
with lower ESR available in larger case sizes. However, the
equivalent series inductance (ESL) of these capacitors
increases with case size and can reduce the usefulness of the
capacitor to high slew-rate transient loading. Unfortunately,
ESL is not a specified parameter. Consult the capacitor
manufacturer and/or measure the capacitor’s impedance with
frequency to help select a suitable component.
Output Inductor Selection
One of the parameters limiting the converter’s response to a
load transient is the time required to change the inductor
current. In a multiphase converter, small inductors reduce
the response time with less impact to the total output ripple
current (as compared to single-phase converters).
The output inductor of each power channel controls the
ripple current. The control IC is stable for channel ripple
current (peak-to-peak) up to twice the average current. A
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ISL8101
single channel’s ripple current is approximated by using
Equation 25.
The current from multiple channels tend to cancel each other
and reduce the total ripple current. The total output ripple
current can be determined using the curve in Figure 11; it
provides the total ripple current as a function of duty cycle
and number of active channels, normalized to the parameter
K
where L is the channel inductor value.
Find the intersection of the active channel curve and duty
cycle for your particular application. The resulting ripple
current multiplier from the y-axis is then multiplied by the
normalization factor, K
ripple current for the given application (see Equation 27).
Δ
I
K
L P-P
I
NORM
NORM
,
TOTAL
1.0
0.8
0.6
0.4
0.2
=
FIGURE 11. RIPPLE CURRENT vs DUTY CYCLE
0
at zero duty cycle (see Equation 26).
=
V
------------------------------- -
=
0
IN
------------------- -
L F
F
K
V
SW
⋅
NORM
OUT
–
V
SW
⋅
OUT
L
0.1
⋅
K
×
CM
V
--------------- -
NORM
V
OUT
IN
DUTY CYCLE (V
0.2
, to determine the total output
0.3
O
/V
IN
)
0.4
July 28, 2008
(EQ. 25)
(EQ. 27)
(EQ. 26)
FN9223.1
0.5