2N5684 NTE ELECTRONICS, 2N5684 Datasheet - Page 3

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2N5684

Manufacturer Part Number
2N5684
Description
T-PNP SI- HI PO AMP SW
Manufacturer
NTE ELECTRONICS
Datasheet

Specifications of 2N5684

Rohs Compliant
YES

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Manufacturer
Quantity
Price
Part Number:
2N5684
Manufacturer:
IDT
Quantity:
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2N5684G
Manufacturer:
ON
Quantity:
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Part Number:
2N5684G
Manufacturer:
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Quantity:
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100
5.0
2.0
1.0
0.5
0.2
0.1
50
20
10
4.0
3.0
2.0
1.0
0.8
0.6
0.4
0.3
0.2
0.07
0.05
0.03
0.02
0.01
1.0
1.0
0.7
0.5
0.3
0.2
0.1
0.5
0.02
Figure 5. Active-Region Safe Operating Area
0.7 1.0
0.02
SINGLE PULSE
0.05
D = 0.5
2.0 3.0
V
CE
0.1
0.2
SECOND BREAKDOWN LIMITED
BONDING WIRE LIMITED
THERMALLY LIMITED @ T
(SINGLE PULSE)
CURVES APPLY BELOW
RATED V
T
, COLLECTOR-EMITTER VOLTAGE (VOLTS)
0.05
J
t
f
= 200°C
t
s
I
C
Figure 6. Turn-Off Time
2N5684 (PNP)
2N5686 (NPN)
, COLLECTOR CURRENT (AMP)
2.0
CEO
5.0
0.01
0.1
3.0
7.0 10
0.2
dc
5.0
2N5684, 2N5686
C
7.0
5.0 ms
= 25°C
20
0.5
500 μs
10
2N5684 (PNP), 2N5686 (NPN)
1.0 ms
30
1.0
Figure 4. Thermal Response
20
T
I
I
V
B1
C
J
CE
50
/I
= 25°C
B
= I
100 μs
= 30 V
= 10
B2
30
http://onsemi.com
70
2.0
100
50
t, TIME (ms)
3
5.0
5000
3000
2000
1000
a transistor: average junction temperature and second
breakdown. Safe operating area curves indicate I
limits of the transistor that must be observed for reliable
operation; i.e., the transistor must not be subjected to greater
dissipation than the curves indicate.
variable depending on conditions. Second breakdown pulse
limits are valid for duty cycles to 10% provided T
v 200_C. T
Figure 4. At high case temperatures, thermal limitations will
reduce the power that can be handled to values less than the
limitations imposed by second breakdown.
700
500
There are two limitations on the power handling ability of
The data of Figure 5 is based on T
θ
θ
D CURVES APPLY FOR POWER
PULSE TRAIN SHOWN
READ TIME AT t
T
0.1
JC
JC
J(pk)
10
(t) = r(t) θ
= 0.584°C/W MAX
- T
0.2
C
= P
20
JC
(pk)
J(pk)
2N5684 (PNP)
2N5686 (NPN)
0.5
1
θ
V
JC
R
Figure 7. Capacitance
, REVERSE VOLTAGE (VOLTS)
(t)
may be calculated from the data in
50
1.0
2.0
100
P
C
(pk)
ib
C
ib
5.0
DUTY CYCLE, D = t
200
t
1
J(pk)
10
t
2
C
ob
500
20
= 200_C; T
T
C
J
ob
= 25°C
1
/t
1000
2
50
C
- V
2000
J(pk)
100
C
CE
is

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